The question involves the knowledge of kinematics and dynamics. The answers are;
a) Time taken to stop the car = 10 s
b) The operation that slows the car is Friction
c) The size of the force = 1200 N
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What is Deceleration ?</h3>
Deceleration is the opposite of acceleration. When an object is going to rest, it will be decelerating and the final velocity will be equal to zero.
Given that the driver of a car moving at 15 m/s along a straight level road applies the brakes. The car decelerates at a steady rate of 3/2 m/s²
a) How long does the car take to stop can be found by using the formula
v = u - at
Where
Substitute all the parameters into the formula
0 = 15 - 1.5t
1.5t = 15
t = 15/1.5
t = 10 s
b) The description of the operation that slows the car down after the brake pedal is pressed is simply friction.
c) If the mass of the car is 800. The size of the force slowing the car down will be F = ma
F = 800 × 1.5
F = 1200 N
Therefore, the time taken to stop the car is 10 s and the force slowing the car down is 1200 N
Learn more about Acceleration here: brainly.com/question/605631
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The kinetic energy of an object is given by
KE = 0.5mv²
where m is the mass and v is the velocity.
To calculate the change in kinetic energy...
Initial KE:
KEi = 0.5mVi²
where Vi is the initial velocity.
Final KE:
KEf = 0.5mVf²
where Vf is the final velocity.
ΔKE = KEf - KEi
ΔKE = 0.5mVi² - 0.5mVf²
ΔKE = 0.5m(Vf²-Vi²)
Given values:
m = 16kg
Vi = 25m/s
Vf = 20m/s
Plug in the given values and solve for ΔKE:
ΔKE = 0.5×16×(20²-25²)
ΔKE = -1800J
Answer:
Refractive index of a medium = Speed of light in vacuum/Speed of light in a medium
1.5 = 3 x 108 / Speed of light in medium
Speed of light in the medium = 3 x 108 /1.5
= 2 x 108 m/s.
Explanation:
true ........i really dont kno but ok hope this helps
