<span>The value of the constant needed to complete in joules to three significant figures is 2.18 x 10^-18 J.</span>
First the velocity drops to zero in 1.2 secs. In those seconds it went upwards for 7.2 m, then it went from 87.2 to 0m. x-x0=v0*t+1/2*g*t^2 ergo t=sqrt(2x/g) that is 4.1761 s. Finally the total time required is 5.3761 s
Answer:
the active region is bound by cutoff region and saturation or power dissipation region.
Explanation:
Since this is a distance/time graph, the speed at any time is the slope
of the part of the graph that's directly over that time on the x-axis.
At time t1 = 2.0 s
That's in the middle of the first segment of the graph,
that extends from zero to 3 seconds.
Its slope is 7/3 . v1 = 7/3 m/s .
At time t2 = 4.0 s
That's in the middle of the horizontal part of the graph
that runs from 3 to 6 seconds.
Its slope is zero.
v2 = zero .
At time t3 = 13 s.
That's in the middle of the part of the graph that's sloping down,
between 11 and 16 seconds.
Its slope is -3/5 . v3 = -0.6 m/s .
Answer:
200 N = 200 Newtons
Explanation:
Just use the formula F = m*a
F = Force in Newtons
m = mass and is 20 kg
a = acceleration and is 10 m/s^2
F = 20 * 10
F = 200 Newtons.
