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Julli [10]
3 years ago
14

What is most likely to be found in both a spinach cell and a muscle cell

Physics
1 answer:
maks197457 [2]3 years ago
4 0
A Myocyte is probably the best answer for this question
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4.0 kg objects mive a distance of 7.8 m under the action of a cinstant gorce of 5.6 N. how much work is dine on object?
alexdok [17]

Answer:

43.68 J

Explanation:

Distance moved= 7.8 m

Force = 5.6 N

Work Done= Distance moved * Force

                   = 7.8 *5.6

                      =43.68 Joules

6 0
3 years ago
What is the relationship between power and voltage?
kipiarov [429]

<u>Answer:</u>

The power and voltage are related through Power Rule .

<u> Explanation : </u>

Power Rule  states  that the current I  that flows the element in the circuit  with a loss in voltage V,  then the amount of  power dissipated by that element in the circuit is the   multiplicative product of  voltage and the current.

Mathematically, power law  is

\boldsymbol{P}=\boldsymbol{I} \times \boldsymbol{V}

The rate of work done or the rate of energy consumption or production is  termed as power.Unit of power is denoted as W(watts).

Potential energy between  any two points on a circuit is called as  Voltage and is measured in volts (V) .

3 0
3 years ago
Question 4. Calculate the kinetic energy of a Year 11 pupil (mass 55Kg)
bogdanovich [222]

Answer:

990 J

Explanation:

Kinetic energy is:

KE = ½ mv²

Given m = 55 kg and v = 6 m/s:

KE = ½ (55 kg) (6 m/s)²

KE = 990 J

4 0
3 years ago
A car accelerates uniformly from +10.0 m/s to +40.0 m/s over a distance of 125 m. How long did it take to go that distance? Show
Marizza181 [45]

Answer:

Explanation:

v^2-u^2=2as\\40^2-10^2=2a*125\\1600-100=250a\\a=\frac{1500}{250}=6~m/s^2\\v=u+at\\40=10+6t\\6t=30\\ t=\frac{30}{6}=5 ~s

7 0
3 years ago
A curve of radius 55.1 m is banked so that a car of mass 1.6 Mg traveling with uniform speed 61 km/hr can round the curve withou
svp [43]

Answer:

θ = 28°

Explanation:

For this exercise We will use the second law and Newton, let's set a System of horizontal and vertical.

X axis

      Fₓ = m a

      Nₓ = m a

Where the acceleration is centripetal

      a = v² / r

The only force that we must decompose is normal, let's use trigonometry

      sin θ = Nₓ / N

      cos θ = N_{y} / N

      Nₓ = N sin θ

      N_{y} = N cos θ

Let's replace

     N sin θ = m v² / r

Y Axis

     N_{y} - W = 0

     N cos θ = mg

Let's divide the two equations of Newton's second law

     Sin θ / cos θ = v² / g r

     tan θ = v² / g r

     θ = tan⁻¹ (v² / g r)

We reduce the speed to the SI system

      v = 61 km / h (1000 m / 1 km) (1h / 3600 s) = 16.94 m / s

Let's calculate

     θ = tan⁻¹ (16.94 2 / (9.8 55.1)

     θ = tan⁻¹ (0.5317)

     θ = 28°

3 0
3 years ago
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