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3 years ago

What is torque in physics ?

Physics

2 answers:

irina [24]3 years ago

8 0

Answer:

Torque is a measure of the force that can cause an object to rotate about an axis.

Paha777 [63]3 years ago

5 0

Answer:

Torque is a measure of how a force acting on an object causes that object to rotate.

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I NEEEED HELPPPPPPP PLEASEEEE

monitta

Answer:

Below

Explanation:

1) To find the average velocity of an object you can use this formula :

v = ∆displacement / ∆time

v = 200 m / 5 s

v = 40 m/s

The average velocity of the turtle is 40 m/s

2) To find the distance an object can travel you can use this formula :

d = (∆velocity)(∆time)

d = (20m/s)(5s)

d = 100 m

The cheetah can run 100 meters in 5 seconds

3) To find the amount of time it takes for an object to move :

t = ∆displacement / ∆velocity

t = 5mi / 20 mph

t = 0.25 h

It would take this car 0.25 h to travel 5 miles at 20 mph

4) To find how far an object can go :

d = (∆velocity)(∆time)

d = (20mph)(3h)

d = 60 mi

The car can drive 60 miles driving 20 mph for 3 hours

5) To find how far an object can go :

d = (∆velocity)(∆time)

d = (20mph)(30min)

d = (20mph)(0.5h)

d = 10 mi

The car can drive 10 miles driving 20mph for 30 minutes

6) To find how long it would take :

t = ∆displacement / ∆velocity

t = 10 m / 50 m/s

t = 0.2 s

It would take the train 0.2 seconds for a train to travel 10 m at 50 m/s

7) To find how far :

d = (∆velocity)(∆time)

d = (670,000,000 mph)(1 yr)

d = (670,000,000 mph)(8760 h)

d = 5869200000000 mi

1 light year is 5869200000000 miles

Hope this helps! Best of luck <3

6 0

3 years ago

When the forces acting moving body are balanced the net force becomes zero. As a result the body will:

WINSTONCH [101]

Answer:

<h2>a</h2><h2> move with an increasing velocity</h2>

5 0

2 years ago

While driving, your car has an initial position of 3.2 m, an initial velocity of -8.4 m/s, and

KIM [24]

Answer:

The position of the car at t = 1.5 s is at -8.1625 meters

Explanation:

The initial position of the car is 3.2 meters

The initial velocity is -8.4 m/s

The constant acceleration is 1.1 m/s²

We need to find the final position of the car at the time t = 1.5 seconds

The displacement <em>s</em> = final position - initial position

$s=ut+\frac{1}{2}at^{2}$ , where <em>u</em> is the initial velocity, <em>a</em> is the

constant acceleration and <em>t</em> is the time

So we can find the final velocity by using the rule:

final position - initial position = $ut+\frac{1}{2}at^{2}$

initial position = 3.2 meters , u = -8.4 m/s , a = 1.1 ²m/s , t = 1.5 s

Substitute these values in the rule

final position - 3.2 = $(-8.4)(1.5)+\frac{1}{2}(1.1)(1.5)^{2}$

final position - 3.2 = -12.6 + 1.2375

final position - 3.2 = -11.3625

add 3.2 for both sides

final position = -8.1625

<em>That means the car is at 8.1625 meters in opposite direction</em>

<em>The position of the car at t = 1.5 s is at -8.1625 meters </em>

4 0

3 years ago

The magnitude of the electrostatic force between two identical ions that are separated by a distance of 5.0A is 3.7×10^-9N.a) wh

jeyben [28]

Explanation:

Given that,

Electrostatic force, $F=3.7\times 10^{-9}\ N$

Distance, $r=5\ A=5\times 10^{-10}\ m$

(a) $F=\dfrac{kq^2}{r^2}$ , q is the charge on the ion

$q=\sqrt{\dfrac{Fr^2}{k}}$

$q=\sqrt{\dfrac{3.7\times 10^{-9}\times (5\times 10^{-10})^2}{9\times 10^9}}$

$q=3.2\times 10^{-19}\ C$

(b) Let n is the number of electrons are missing from each ion. It can be calculated as :

$n=\dfrac{q}{e}$

$n=\dfrac{3.2\times 10^{-19}}{1.6\times 10^{-19}}$

n = 2

Hence, this is the required solution.

8 0

3 years ago

What is the magnitude of velocity for a 2000 kg car possessing 3000 kgm/s of momentum

Alex

For this case we have that by definition, the momentum is given by:

$p = mv$

Where,

<em>m: mass </em>
<em>v: speed </em>

Therefore, replacing values we have:

$3000 = (2000) v$

From here, we clear the value of the speed:

$v = \frac {3000} {2000}\\v = 1.5 \frac {m} {s}$

Answer:

The magnitude of velocity is:

$v = 1.5 \frac {m} {s}$

4 0

3 years ago

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