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3 years ago

What do the symbols mean???

Physics

1 answer:

Elena L [17]3 years ago

8 0

1. Fixed resistor ; A resistor is used to reduce the flow of electricity in an electric circuit. Resistors come in fixed or variable types. A fixed resistor cannot be changed as it is set at a specific value, whereas a variable resistor can manage flows at and below a specific level.

2. Variable Resistor ;

An electronic component that is used to vary the amount of current that flows through a circuit. It works by sliding a wiper terminal across a resistive material, typically a thin film or chunk of carbon or a resistive wire made of nickel chromium or tungsten alloys.

3. Thermistor ;

Converts heat to electrical resistance.

4. Light dependant resistor ;

Converts light to electrical resistance.

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The following position vs time graph shows the motion of an object along its path from -10 to seconds. Based on this graph, what

Marrrta [24]

∆x (displacement) = v - u

where, v is the final position and u is the initial position.

Given, the final position of the object is 0 m and the initial position is 5 m.

∆x (displacement) = v - u

= 0 m - 5 m

= -5 m

Therefore, <u>C: -5m</u> is the correct answer.

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3 years ago

A sample of a gas has a volume of 52 l at a pressure of 1.2 atm. what volume will the gas occupy if the pressure is changed to 0

Shtirlitz [24]

<h2>Equation of state of an ideal gas</h2>

<em>The </em><em>ideal gas law is derived</em><em> from the ga</em><em>s laws of Boyle, Charles, Gay Lussac and General.</em>

To solve this exercise, we obtain the data of the exercise:

V₁ = 52 Lt
P₁ = 1,2 atm
P₂ = 0.75 atm
V₂ = ¿?

<em>The general formula of the </em><em>Equations of state of an ideal gas is:</em>

<h3>P₁V₁=P₂V₂, Where</h3>

P₁ = Initial pressure
V₁ = Initial volume
P₂ = End Pressure
V₂ = Final Volume

We clear the formula, since it is the value that we must calculate.

To solve, we substitute our data in the formula; and we solve

Answer:<em> The </em><em>volume that the gas will occupy</em><em> if the pressure increases to 0.75 atm is </em><em>0.832 lt.</em>

<h2>See more about this at:</h2><h3>brainly.com/question/15907283</h3>

3 0

2 years ago

The gravitational attraction between a 20 kg cannonball and a 0.002 kg

Naya [18.7K]

Answer:

$2.966\times 10^{-11}\ N$

Explanation:

Given:

Mass of the cannonball (M) = 20 kg

Mass of the marble (m) = 0.002 kg

Distance between the cannonball and marble (d) = 0.30 m

Universal gravitational constant (G) = $6.674\times 10^{-11}\ m^3 kg^{-1} s^{-2}$

Now, we know that, the gravitational force (F) acting between two bodies of masses (m) and (M) separated by a distance (d) is given as:

$F=\dfrac{GMm}{d^2}$

Plug in the given values and solve for 'F'. This gives,

$F=\frac{(6.674\times 10^{-11}\ m^3 kg^{-1} s^{-2})\times (20\ kg)\times (0.002\ kg)}{(0.30\ m)^2}\\\\F=\frac{6.674\times 20\times 0.002\times 10^{-11}\ m^3 kg^{-1+2} s^{-2}}{0.09\ m^2}\\\\F=2.966\times 10^{-11}\ kg\cdot m\cdot s^{-2}\\\\F=2.966\times 10^{-11}\ N.........(1\ N = 1\ kg\cdot m\cdot s^{-2})$

The same force is experienced by both cannonball and marble.

Therefore, the gravitational force of the marble is $2.966\times 10^{-11}\ N$

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3 years ago

. A student times a car traveling a distance of 2 m. She finds that it takes the car 5 s to

AveGali [126]

No, the car travels 1 metre in 5s at the start which is 0.2m/s, while the second meter it travels one metre in 8 seconds which is 0.125 m/s, the speed changes therefore it is not constant during the two metres the car travels

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3 years ago

On hot sunny days or days with thin clouds, the temperature over the land is warmer than the temperature over the water. The war

Luden [163]

Answer:

i think it would be a but i am not 100% sure on that

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3 years ago