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elena55 [62]
3 years ago
12

An object goes from 10 m/s to 2 m/s in 2 seconds, what's its acceleration?

Physics
1 answer:
Mila [183]3 years ago
6 0

Answer:

a=(v-u)÷t

a= (2-10)÷2

a= -8÷2

a= -4 m/s²

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What was the most serious money problem faced by people in the early United States?
alexira [117]
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5 0
3 years ago
In order to determine the coefficients of friction between rubber and various surfaces, a student uses a rubber eraser and an in
Strike441 [17]

Answer:

μs = 0.75

μk = 0.58

Explanation:

From a force diagram:

m*g*sin \theta - Ff=m*a     (1)

N-m*g*cos \theta = 0         (2)

When it starts slipping, friction force is the maximum and acceleration is 0. Replacing these conditions on (1):

m*g*sin \theta - \mu*m*g*cos \theta=0   Solving for μs:

\mu=tan \theta

μs = tan 36.7° = 0.75

When it moves at constant speed, friction force is kinetic friction and acceleration is 0. With these conditions the coefficient is:

μk = tan 30.1° = 0.58

8 0
4 years ago
A system has 4 independent and identical motors, in order for the system to work, at least one of the motors must operate. Each
grin007 [14]

Answer:

The system's Mean Time to Failure is 1,041.\bar 6 hours

Explanation:

The number of independent identical motors = 4

The failure rate of each motor, λ = 0.002 failures per hour

Given that in order for the system to work, at least one of the motors must operate, therefore, the system are in parallel

The Mean Time to Failure for a parallel system of four identical components is given as follows;

MTTF = \dfrac{1 }{\lambda} \times \left (1 + \dfrac{1}{2} +  \dfrac{1}{3} + \dfrac{1}{4} \right)

Which gives;

MTTF = \dfrac{1 }{0.002} \times \left (1 + \dfrac{1}{2} +  \dfrac{1}{3} + \dfrac{1}{4} \right) = 1,041.\bar 6

The system's Mean Time to Failure = 1,041.\bar 6 hours.

8 0
3 years ago
A grasshopper floating in water generates waves at a rate of three per second with a wavelength of two centimeters. (a) What is
Nastasia [14]

Answer:

(a) 0.33 second

(b) 6 cm/s

Explanation:

Frequency, f = 3 waves per second

wavelength, λ = 2 cm = 0.02 m

(a) The period of wave is defined as the time taken by the wave to complete one oscillation. It is the reciprocal of frequency.

T = 1 / f = 1 / 3 = 0.33 second

(b) the relation between wave velocity, frequency and wavelength is given by

v = f x λ

v = 3 x 0.02 = 0.06 m /s

v = 6 cm /s

8 0
3 years ago
22. On a day the wind is blowing toward the south at 3m/s, a runner jogs west at 4m/s. What is the velocity of the air relative
blagie [28]

The velocity of the air relative to the runner is 5 m/s.

<h3>What is the relative velocity?</h3>

We must recall that velocity is a vector quantity and the relative velocity must be obtained vectorially. Thus we know that;

Velocity of the runner = 4m/s. due west

Velocity of the wind =  3m/s due south

The relative velocity is;

Vr = √(4)^2 + (3)^2

Vr = 5 m/s

Learn more about relative velocity:brainly.com/question/20813206

#SPJ1

3 0
2 years ago
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