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ra1l [238]
3 years ago
9

On hot sunny days or days with thin clouds, the temperature over the land is warmer than the temperature over the water. The war

mer air rises and the cooler air moves over the land, producing sea breezes. This means that,
A: Water takes longer to heat up than the land
B: Soil warms up more slowly than the water
C: The air above the land becomes cool and rises
D: Land takes longer to heat up tan the water
Physics
1 answer:
Luden [163]3 years ago
4 0

Answer:

i think it would be a but i am not 100% sure on that

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An ordinary egg can be approximated as a 5.5-cm diameter sphere. The egg is initially at a uniform temperature of 8°C and is dro
kupik [55]

Answer:

a) Q_{in} = 13.742\,kW, b) \Delta S = 370.15\,\frac{kJ}{K}

Explanation:

a) The heat transfered to the egg is computed by the First Law of Thermodynamics:

Q_{in} +U_{sys,1} - U_{sys,2} = 0

Q_{in} = U_{sys,2} - U_{sys,1}

Q_{in} = \rho_{egg}\cdot \left(\frac{4\pi}{3}\cdot r^{3}\right)\cdot c \cdot (T_{2}-T_{1})

Q_{in} = \left(1020\,\frac{kg}{m^{3}}\right)\cdot \left(\frac{4\pi}{3}\right)\cdot (0.025\,m)^{3}\cdot \left(3.32\,\frac{kJ}{kg\cdot ^{\textdegree}C} \right)\cdot (70\,^{\textdegree}C - 8\,^{\textdegree}C)

Q_{in} = 13.742\,kW

b) The amount of entropy generation is determined by the Second Law of Thermodynamics:

\Delta S = \frac{Q_{in}}{T_{in}}

\Delta S = \frac{13.742\,kJ}{370.15\,K}

\Delta S = 370.15\,\frac{kJ}{K}

3 0
3 years ago
Which is the pathway for information through a neuron?
Mariulka [41]
Information travels along the axon once an impulse is received. The axon then takes it to the place where it can be sent off to another neuron

<span>dendrite → cell body → axon → axon terminals is the correct answer</span>

<span>If I managed to help you, please make sure to mark my answer as the "Brainliest" answer. Thanks! :)</span>
6 0
3 years ago
Read 2 more answers
HELP PLZ ASAP!!
Andre45 [30]
1. The successful launch of communication satellites

2.More people will be interested in studying science

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5 0
2 years ago
The force of attraction between two oppositely charged pith is 5mx 10 to the -6th power newtons. If the charge on the two is 6.7
My name is Ann [436]

Answer:

0.28 m

Explanation:

The following data were obtained from the question:

Force (F) = 5×10¯⁶ N

Charge 1 (q₁) = 6.7×10¯⁹ C

Charge 2 (q₂) = 6.7×10¯⁹ C

Electrical constant (K) = 9×10⁹ Nm²C¯²

Distance apart (r) =?

Thus, the distance between the two charges can be obtained as follow:

F = Kq₁q₂/r²

5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²

5×10¯⁶ = 4.0401×10¯⁷ / r²

Cross multiply

5×10¯⁶ × r² = 4.0401×10¯⁷

Divide both side by 5×10¯⁶

r² = 4.0401×10¯⁷ / 5×10¯⁶

Take the square root of both side

r = √(4.0401×10¯⁷ / 5×10¯⁶)

r = 0.28 m

Therefore, the distance between the two charges is 0.28 m

4 0
2 years ago
How long can a person dribble a ball when being closely guarded by a
Katena32 [7]

Answer:

four seconds

Explanation:

A player who catches the ball and is being closely guarded may hold the ball for four seconds, then dribble the ball for four seconds, then hold the ball for another four seconds, then pass, will not be in violation of this rule.

7 0
3 years ago
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