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Answer:
The car has an energy of 1.017 × 10⁵ J when it moves at 97 miles per hour
Explanation:
Given the data in the question;
Initial velocity v₁ = 68 miles per hour = 30.398 meter per seconds
let mass of the car be m
kinetic energy of that car is 5 × 10⁵ J
so
E₁ = mv²
we substitute
5 × 10⁵ = × m × ( 30.398 )²
5 × 10⁵ = × m × ( 30.398 )²
5 × 10⁵ = m × 462.019
m = 5 × 10⁵ / 462.019
m = 1082.2065 kg
Now, Also given that; v₂ = 97 miles per hour = 43.362 meter per seconds
E₂ = mv₂²
we substitute
E₂ = × 1082.2065 × ( 43.362 )²
E₂ = × 1082.2065 × 1880.263
E₂ = 1.017 × 10⁵ J
Therefore, The car has an energy of 1.017 × 10⁵ J when it moves at 97 miles per hour
The coefficient of static friction is the ratio of the maximum static friction force (F) between the surfaces in contact before movement commences to the normal (N) force.
<h3>What is coefficient of static friction formula?</h3>- The friction coefficient is the ratio of the normal force pushing two surfaces together to the frictional force preventing motion between them.
- Typically, it is represented by the Greek letter mu (). In terms of math, is equal to F/N, where F stands for frictional force and N for normal force.
- The ratio of the greatest static friction force (F) between the surfaces in contact before movement starts to the normal force (N) is known as the coefficient of static friction.
- A body and a surface have static and kinetic friction coefficients of 0.75 and 0.5, respectively. The body is forced to slide with a constant acceleration that is equal to A. g4 by applying a force.
Find the attachment answer.
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