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marusya05 [52]
3 years ago
11

After observing a moth that is camouflaged against dark-colored bark, a scientist asks a question. The scientist discovers that

the question has already been asked and answered by several investigations. What should the scientist do?The scientist should test the question anyway.
The scientist should broaden the scope of the question.
The scientist should come up with a new way to test the question.
The scientist should revise the question to address a gap in knowledge.
Physics
2 answers:
Rasek [7]3 years ago
6 0
Because of how it's worded the answer would most likely be number four                                                                                       

liq [111]3 years ago
6 0

Answer: The scientist should revise the question to address a gap in knowledge.

Explanation:

A research question is a scientific inquiry that is required to be answered using suitable methodology.

Among the options given, The scientist should revise the question to address a gap in knowledge. is the correct option. This is because of the fact that analyzing and finding the possibilities in the question again the scientist can add new facts in the question which have not been found out by the research conducted by the several scientists earlier. This will lead to the increment in the knowledge related to the research topic.

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Identical isolated conducting spheres 1 and 2 have equal charges and are separated by a distance that is large compared with the
scoundrel [369]

Answer:

F = 0.1575 N

Explanation:

When the third sphere touches the first sphere, the charge is distributed between both spheres, then now the first sphere has only half of his original charge.

In this moment then

Sphere one has a charge = Q/2

Sphere three has a charge = Q/2

Now when the third sphere touches the second sphere again the charge is distributed in a manner that both sphere has the same charge.

How the total charge is Q = Q/2 + Q = 3/2Q, when the spheres are separated each one has 3/4Q

Sphere two has a charge = 3/4Q

Sphere three has a charge = 3/4Q

The electrostatic force that acts on sphere 2 due to sphere 1 is:

F = \frac{kQ_{1}Q_{2} }{r^{2} }

F= \frac{K(Q/2)(3Q/4)}{r^{2} }

how \frac{KQ^{2} }{r^{2} } = 0.42

Then

F = \frac{0.42*3}{8}

F = 0.1575 N

3 0
3 years ago
In an LC circuit containing a 40-mH ideal inductor and a 1.2-mF capacitor, the maximum charge on the capacitor is 45mC during os
GalinKa [24]

Answer:

E) 6.5 A

Explanation:

Given that

L = 40 m H

C= 1.2 m F

Maximum charge on capacitor ,Q= 45 m C

The maximum current I given as

I = Q.ω

ω =angular frequency

\omega=\dfrac{1}{\sqrt{CL}}

By putting the values

\omega=\dfrac{1}{\sqrt{CL}}

\omega=\dfrac{1}{\sqrt{40\times 10^{-3}\times 1.2 \times 10^{-3}}}

ω  = 144.33 rad⁻¹

Maximum current

I = 45 x 10⁻³ x 144.33  A

I= 6.49 A

I = 6.5 A

E) 6.5 A

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