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Varvara68 [4.7K]
2 years ago
10

How does the density of a gas affect the speed of sound

Chemistry
1 answer:
ZanzabumX [31]2 years ago
4 0

Increased density decreases the speed of sound in a medium. While increased density can mean increased rigidity, or stiffness, it is not always the case. Greater density can be due to each molecule or atom having more momentum, and being slower to respond to the vibration of its neighbor.

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Which orbital is the first to fill with electrons in a given principal energy level?
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e) both s and p

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Describe the three values in a learner-centred curriculum that a teacher can use
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to talk in a way that the class can all understand . help them in thing they are falling . and have a good relashaship.

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2 years ago
B) draw the structure of ethane in line-bond mode. (do not draw the hydrogen atoms.)
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There are two ways to represent the chemical formula of a substance: in condensed form or in structural form. Ethane is an alkane which consist of two carbon atoms. Since the general formula for ethane is CₓH₂ₓ₊₂, the condensed formula is C₂H₆. The structural formula or the line-bond structure is shown in the attached picture.

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3 years ago
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Melamine, C3N3(NH2)3, is used in adhesives and resins. It is manufactured in a two-step process: CO(NH2)2(l) → HNCO(l) + NH3(g)
svetlana [45]

Answer:

43.13Kg of melamine

Explanation:

The problem gives you the mass of urea and two balanced equations:CO(NH_{2})_{2}_{(l)}=HNCO_{(l)}+NH_{3}_{(g)}

6HNO_{l}=C_{3}N_{3}(NH_{2})_{3}_{(l)}+3CO_{2}_{(g)}

First we need to calculate the number of moles of urea that are used in the reaction, so:

molar mass of urea = 60.06\frac{g}{mol}*\frac{1kg}{1000g}=0.06006\frac{Kg}{mol}

The problem says that you have 161.2Kg of urea, so you take that mass of urea and find the moles of urea:

161.2Kg of urea*\frac{1molofurea}{0.06006Kgofurea}=2684 moles of urea

Now from the stoichiometry you have:

2684 moles of urea*\frac{1molofHNCO}{1molurea}*\frac{1molofmelamine}{6molesofHNCO} = 447 moles of melamine

The molar mass of the melamine is 126.12\frac{g}{mol} so we have:

447molesofmelamine*\frac{126.12g}{1molofmelamine} = 5637.64 g of melamine

Converting that mass of melamine to Kg:

5637.64 g of melamine *\frac{1Kg}{1000g} = 56.38 Kg of melamine, that is the theoretical yield of melamine.

Finally we need to calculate the mass of melamine with a yield of 76.5%, so we have:

%yield = 100*(Actual yield of melamine / Theoretical yield of melamine)

Actual yield of melamine = \frac{76.5}{100}*56.38Kg = 43.13Kg of melamine

8 0
3 years ago
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