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4 years ago

10

Solve for y. 22mm+15mm+(4y+12)mm=180 degrees

1 answer:

AURORKA [14]4 years ago

3 0

Answer:

y = 45/m^2 − 49/4

Isolate the variable by dividing each side by factors that don't contain the variable

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All zeros of the polynomial function 3x^3 + 2x^2

Softa [21]

Answer:

$x = 0, -2/3$

Step-by-step explanation:

<u>Step 1: Factor out an x^2</u>

<u /> $3x^3+2x^2$

$x^2(3x + 2)$

<u>Step 2: Find the zeros</u>

<u /> $\sqrt{x^2 } = \sqrt{0}$

$x = 0$ → Double Root

$3x + 2 - 2 = 0 - 2$

$\frac{3x}{3} = \frac{-2}{3}$

$x = -2/3$ → Single Root

Answer: $x = 0, -2/3$

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3 years ago

Slausonn can you pls answer this quesion pls i have 3 min left

andrey2020 [161]

6 and 17
m+m+1=33
2m=32
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3 years ago

How do you divide & multiply decimals?<br> Please give me an example of at least one

mylen [45]

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3 years ago

If thewronskian w of f and g is 3e4t,and if f(t) = e2t,find g(t).

ehidna [41]

$W(f(x),g(x))=\begin{vmatrix}f(x)&g(x)\\f'(x)&g'(x)\end{vmatrix}=f(x)g'(x)-g(x)f'(x)$

We have $f(t)=e^{2t}\implies f'(t)=2e^{2t}$ , so

$W(f(t),g(t))=e^{2t}g'(t)-2e^{2t}g(t)=3e^{4t}$
$\implies e^{-2t}g'(t)-2e^{-2t}g(t)=3$
$\implies\dfrac{\mathrm d}{\mathrm dt}[e^{-2t}g(t)]=3$
$\implies e^{-2t}g(t)=\displaystyle\int3\,\mathrm dt$
$\implies e^{-2t}g(t)=3t+C$
$\implies g(t)=3te^{2t}+Ce^{2t}$

where $C$ is any arbitrary constant.

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4 years ago

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Dmitry [639]

Answer:

all work is shown and pictured

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3 years ago