Actually the correct answer must be:
The limiting reactant in the reaction is the one which has
the lowest ratio of moles available
over coefficient in the balanced equation
This is because the actual mass or number of moles of the
reactant does not directly dictate if it is a limiting reactant, this must be
relative to the other reactants.
So the answer is:
e. none of the above
Answer:
We need 41.2 L of propane
Explanation:
Step 1: Data given
volume of H2O = 165 L
Step 2: The balanced equation
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)
Step 3: Calculate moles of H2O
1 mol = 22.4 L
165 L = 7.37 moles
Step 4: Calculate moles of propane
For 1 mol C3H8 we need 5 moles O2 to produce 3 moles CO2 and 4 moles H2O
For 7.37 moles H2O we need 7.37/4 = 1.84 moles propane
Step 5: Calculate volume of propane
1 mol = 22.4 L
1.84 moles = 41.2 L
We need 41.2 L of propane
Answer:
single displacement reaction
Answer:
Protons, neutrons, and electrons: Both protons and neutrons have a mass of 1 amu and are found in the nucleus. However, protons have a charge of +1, and neutrons are uncharged. Electrons have a mass of approximately 0 amu, orbit the nucleus, and have a charge of -1.
Explanation:
Answer:
the concentration is 10^(-8) M
