Answer:
1. 7.256g of NaCl
2. 47.33g of Cl2
Explanation:
2 moles of Na reacts to produce 2 moles of NaCl
8 moles of Na will still produce 8 moles of NaCl
Mass of NaCl = molar mass of Nacl/moles of Nacl
=58.5/8
=7.256g of NaCl
From the equation, 2 moles of Na reacts with 1 mole of Cl2
3/2 moles of Cl2 will react with 3 moles of Na
Mass of Cl2 = 71/1.5
=47.33g of Cl2
Answer:
hope it is correct and helps you
good luck
Hey there!:
Copper plating on Zinc will occur via this simple reaction:
Cu²⁺ + 2 e⁻ ⇌ Cu
When a species gains electron, it is reduced. Its oxidation state is decreased. For example, in the above reaction Cu2+ gained 2 electron to get reduced to Cu. Its oxidation state changed from +2 to 0. Hence it is a reduction reaction.
So, the correct answer is :
The copper II ions gain two electrons and are reduced.
Answer B
Hope this helps!
Answer:
Molarity = 0.202 M
7.36 g/L HCl
Explanation:
KOH + HCl ----> KCl + H2O
1 mol 1 mol
0.560mol/L *0.045L x mol/L*0.125L
0.560mol/L *0.045L = x mol/L*0.125L
x = 0.560mol/L *0.045L /0.125L= 0.2016 mol/L≈ 0.202 mol/L=0.202M HCl
M(HCl) = 1.0+35.5 = 36.5 g/mol
0.2016 mol/L*36.5 g/mol ≈ 7.36 g/L HCl