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3 years ago

Assume that you have no limit on the amount of money you can spend on a tennis racket. What kind

Chemistry

1 answer:

Taya2010 [7]3 years ago

7 0

Answer:

I would buy a high quality racket and a racket that would enhance your abilities more. I would buy one that helps you in any way possible if you just buy one for looks then ur screwed

Explanation:

You might be interested in

UHHH helpppp maya cause uh she d.a.n.g d.u.m.b.

inna [77]

Answer:

Explanation:

the mass number of the element which is protons and neutrons is 17+18=35

electronic configuration is 2, 8, 7

valency of the element is 1 therefore the atomic number is 17

6 0

2 years ago

Read 2 more answers

Element X is in group 2, and element Y is in group 7, of the periodic table. which ions will be present in the compound formed w

12345 [234]

Answer:

Element X has valency 2 while Y Valency 2, element Y has high tendency of gaining electrons for its stability thus the compound formed will be B

elements X is positively charged while Y will be negatively charged

8 0

2 years ago

Give the chemical symbol for the element with the ground‑state electron configuration [ Ar ] 4 s 2 3 d 1 . symbol: Determine the

Rus_ich [418]

Answer:

Sc (Scandium) has the given electronic configuration.

Explanation:

The given electronic configuration is [Ar] $4s^{2}3d^{1}$ .

The last electron enters the d-subshell and hence is a d-block element known as Scandium with chemical symbol Sc.

For 4s subshell

n=4,l=0 and m ranges from -l to +l so m=0.

For 3d subshell

n=3,l=2 and m ranges from -l to +l so m can take values -2,-1,0,+1,+2

Note:

l values for subshells:

s : 0

p : 1

d : 2

f : 3 and so on.

5 0

2 years ago

) Given the following balanced equation, determine the rate of reaction with respect to [O2]. If the rate of formation of O2is 7

Travka [436]

Answer:

Rate of the reaction is 0.2593 M/s

-0.5186 M/s is the rate of the loss of ozone.

Explanation:

The rate of the reaction is defined as change in any one of the concentration of reactant or product per unit time.

$2O_3\rightleftharpoons 3O_2$

Rate of formation of oxygen : $7.78\times 10^{-1} M/s$

Rate of the reaction(R) = $\frac{-1}{2}\frac{d[O_3]}{dt}=\frac{1}{3}\frac{d[O_2]}{dt}$

$R=\frac{1}{3}\frac{d[O_2]}{dt}$

Rate of formation of oxygen=3 × (R)

$7.78\times 10^{-1} M/s=3\times R$

Rate of the reaction(R): $0.2593 M/s$

Rate of the reaction is 0.2593 M/s

Rate of disappearance of the ozone:

$R=-\frac{1}{2}\frac{d[O_3]}{dt}$

$\frac{d[O_3]}{dt}=-2\times R=-2\times 0.2593\times M/s=-0.5186M/s$

-0.5186 M/s is the rate of the loss of ozone.

6 0

3 years ago

How any moles of H2O will be produced from 12.3 moles of HCL reacting with Ca(OH)2?

stiks02 [169]

Answer:

\large \boxed{\text{12.3 mol HCl}}

Explanation:

We need a balanced chemical equation with moles.

2HCl +Ca(OH)₂ ⟶ CaCl₂ + 2H₂O

n/mol: 12.3

The molar ratio is 2 mol H₂O:2 mol HCl.

$\text{Moles of H$_{2}$O} = \text{12.3 mol HCl} \times \dfrac{\text{2 mol H$_{2}$O}}{\text{2 mol HCl}} = \textbf{12.3 mol HCl}\\\\\text{The reaction produces $\large \boxed{\textbf{12.3 mol HCl}}$}$

3 0

3 years ago