Answer: good luck with that F
Explanation:
Answer:
tetrahedral
As carbon has no 4 valence electrons that are occupied by 4 chlorine atoms, we get 0 lone pair in carbon and sp3 hybridisation which leads to tetrahedral shape.
Answer:
<em>2.54 mol CO2 </em>
Explanation:
To calculate the mol of carbon dioxide that will be generated by megajoule (MJ). First, we have to find the value of the formation enthalpy for the CO2 at standard conditions.
<em>Remember that standard conditions are at 25°C and 1 atm. </em>
Any physic chemistry book has the table of ΔHf°, I always use one name Levine's physic chemistry. You can trust its data.
Enthalpy of formation for CO2: -393.509 kJ/mol
As you can see this value means that for each 393.509 kJ liberate (that's indicated for the menus sing), 1 mol of CO2 is formed.
Let's write this using mathematic language:
393.509 kJ/ 1 mol CO2
The problem asks you to find how many mols are produced by 1 megajoule liberate, let's change megajoule to kilojoule.
1 megajoule (MJ) = 1000 kJ
1000 kJ x (1mol/ 393.509 kJ) = 2.54 mol CO2
<em>Remember don't use the negative value to make the calculus. The negative value just indicates that the heat is been released.</em>
If you want to watch the mathematics details, go to the image attached.
500 because F1 is 500 x 1. Tell me if I’m right. Good luck!
You have to take the longest chain with the functional group as the main chain. Which means the name will end in ‘hex-1-ene’. The ‘1’ is for the place of the functional group. This has to be the smallest number possible. So no ‘hex-5-ene’. Then for the first part, we need to say something about the place and the kind of the branch. In this case, it is a propylgroup on the 4th carbon of the main chain. We will not take the 3rd carbon because we already decided to count from the right. The total name will then be: ‘4-propylhex-1-ene’.