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3 years ago

A 2.10 X 10^3 kg car starts from rest at the top of a 5.0

Physics

1 answer:

xeze [42]3 years ago

4 0

Answer:

3.80 m/s

Explanation:

Solution: From the question we have:

A 2.10 x 10^3 kg car starts from rest at the top of a 5.0 m long driveway that is sloped at 20 degrees with the horizontal.

average friction force of 4.0 x 10^3 N impedes the motion

To find out: find the speed of the car at the bottom of the driveway.

=>h = 5×sin20 = 1.71 m.

PE = mgh = 2100×9.8×1.71 = 35,192 J.

KE = PE-work done by frictional force

KE=PE-4000×5

0.5mV^2 = 35192 - 4000×5

1050V^2 = 15,192

V^2 = 14.47

V = 3.80 m/s.

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If the pressure exerted on a 300.0 mL sample of hydrogen gas at constant temperature is increased from 0.500 kPa to 0.750 kPa, w

uranmaximum [27]

Answer:

200 mL

Explanation:

Given that,

Initial volume, V₁ = 300 mL

Initial pressure, P₁ = 0.5 kPa

Final pressure, P₂ = 0.75 kPa

We need to find the final volume of the sample if pressure is increased at constant temperature. It is based on Boyle's law. Its mathematical form is given by :

$V\propto \dfrac{1}{P}\\\\P_1V_1=P_2V_2$

V₂ is the final volume

$V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{300\times 0.5}{0.75}\\\\V_2=200\ mL$

So, the final volume of the sample is 200 mL.

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3 years ago

How does the flatter design make sweeping the floor easier

Ratling [72]

Answer:

there will be no cracks so the trash won't get stuck

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3 years ago

Consider a box sitting in the back of a pickup. The pickup accelerates to the right, and because the bed of the pickup is sticky

andreyandreev [35.5K]

The force would be coming from the right causing the box the lean/ slide to left, if it wasnt sticky.

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4 years ago

A person applies a force of 67 N for a distance of 11 m to push a desk across the floor. How much work is done

lbvjy [14]

L=F*d=67*11=737 Joule

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3 years ago

A man is traveling from the back of a boat to the front of the boat at 2.0 m/s while the boat itself is traveling at 12.0 m/s to

Hatshy [7]

Based on the relative velocity of the man with respect to the boat and the dock:

Distance covered in 4.0 seconds relative to the boat = 8 m
Distance covered in 4.0 seconds relative to the dock = 56 m

<h3>What is relative velocity?</h3>

Relative velocity is the velocity of a body relative to another body which serves as a reference point.

Relative velocity is a vector.

Considering the velocity of the man and the boat:

The relative velocity of the man with respect to the boat = 2.0 m/s

Distance covered in 4.0 seconds relative to the boat = 2.0 m/s * 4.0 s

Distance moved = 8 m

Relative velocity of the man with respect to the dock = 12 + 2 = 14 m/s

Distance covered in 4.0 seconds relative to the dock = 14.0 m/s * 4.0 s

Distance moved = 56 m

In conclusion, the relative velocity is velocity with respect to a reference point.

Learn more about relative velocity at: brainly.com/question/24337516

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5 0

2 years ago