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scoundrel [369]
3 years ago
10

You can describe the _______________ of an object by saying it is moving in a straight line or is curved around another object.

You can also describe where an object is by its _______________ in relation to another object. The second object acts as a _______________ point. When an object changes position, you know it has motion. Motion can also be described by finding an object's _______________, or how fast or slow it moves in a certain amount of time. In addition, you can describe the object's speed AND direction together. This is called _______________.
Physics
1 answer:
velikii [3]3 years ago
7 0

Answer:

You can describe the<u> motion </u>of an object by saying it is moving in a straight line or is curved around another object. You can also describe where an object is by its <u> position </u> in relation to another object. The second object acts as a<u> reference</u> point. When an object changes position, you know it has motion. Motion can also be described by finding an object's <u>speed  </u>or how fast or slow it moves in a certain amount of time. In addition, you can describe the object's speed AND direction together. This is called <u>velocity</u>

Explanation:

In the given answer-

<u>Motion</u> is defined as - the change in the movement or position of any object  or body.

<u>Position</u> is said to be a place or somewhere or a location where any object or body is particularly placed/located or put on.

<u>Reference poin</u>t is a fixed point with regards to which any object or body changes its position. It is also called reference origin.

<u>Speed</u> is defined as the rate of any object covering certain distances. It is a scaler quantity (quantity which depends upon only magnitude).

<u>Velocity</u> is defined as the rate of speed per unit time. It is a vector quantity (quantity depending upon both magnitude and direction ).

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To test the performance of its tires, a car
velikii [3]

<u>Answer</u>:

The coefficient of  static friction between the tires and the road is 1.987

<u>Explanation</u>:

<u>Given</u>:

Radius of the track, r =  516 m

Tangential Acceleration a_r=  3.89 m/s^2

Speed,v =  32.8 m/s

<u>To Find:</u>

The coefficient of  static friction between the tires and the road = ?

<u>Solution</u>:

The radial Acceleration is given by,

a_{R = \frac{v^2}{r}

a_{R = \frac{(32.8)^2}{516}

a_{R = \frac{(1075.84)}{516}

a_{R = 2.085 m/s^2

Now the total acceleration is

\text{ total acceleration} = \sqrt{\text{(tangential acceleration)}^2 +{\text{(Radial acceleration)}^2

=>= \sqrt{ (a_r)^2+(a_R)^2}

=>\sqrt{ (3.89 )^2+( 2.085)^2}

=>\sqrt{ (15.1321)+(4.347)^2}

=>19.4791 m/s^2

The frictional force on the car will be f = ma------------(1)

And the force due to gravity is W = mg--------------------(2)

Now the coefficient of  static friction is

\mu =\frac{f}{W}

From (1) and (2)

\mu =\frac{ma}{mg}

\mu =\frac{a}{g}

Substituting the values, we get

\mu =\frac{19.4791}{9.8}

\mu =1.987

8 0
3 years ago
How much work will it take to lift a 2-kg pair of hiking boots 2 meters off the
AnnyKZ [126]

Answer:

Option C - 39.2 J

Explanation:

We are given that;

Mass; m = 2 kg.

Distance moved off the floor;d = 10 m.

Acceleration due to gravity;g = 9.8 m/s².

We want to find the work done.

Now, the Formula for work done is given by;

Work = Force × displacement.

In this case, it's force of gravity to lift up the boots, thus;

Formula for this force is;

Force = mass x acceleration due to gravity

Force = 2 × 9.8 = 19.2 N

∴ Work done = 19.6 × 2

Work done = 39.2 J.

Hence, the Work done to life the boot of 2 kg to a height of 2 m is 39.2 J.

7 0
3 years ago
Read 2 more answers
Periodic table of elements metals and nonmetals questions
bixtya [17]

Answer:

1 o b

2 c\

3 a

Explanation:

5 0
2 years ago
Read 2 more answers
3. Consider a locomotive and the rest of a freight train to be a single object. Suppose the locomotive is pulling the train up a
Nonamiya [84]

Answer:

Action - Pulling up the train.

Reaction - Friction on the locomotive

Explanation:

Locomotive is pulling the train upwards ,

Which is the action force applied by the locomotive,

As a reaction locomotive will be pulled by the train which is the reaction of pulling

Now, considering it as a action on locomotive , friction force will act on it as a reaction upwards which will result to move it upwards.

For train action is pulling up by locomotive and reaction will be friction acting on it downwards.

6 0
3 years ago
The transfer of energy in liquids and gases as groups of molecules move in currents is
AlexFokin [52]
Convection is your answer
8 0
3 years ago
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