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2 years ago

A sound wave traveling in water at 144m/s has a wavelength of 0.5m determine the frequency of the wave

Physics

2 answers:

mrs_skeptik [129]2 years ago

4 0

Heya!!

For calculate frequency, lets applicate formula:

$\boxed{f=v/\lambda}$

<u>Δ Being Δ</u>

f = Frequency = ?

v = Velocity = 144 m/s

$\lambda$ = Wavelenght = 0,5 m

⇒ Let's replace according the formula:

$\boxed{f = 144\ m/s / 0,5\ m }$

⇒ Resolving

$\boxed{f = 288\ Hz}$

Result:

The frequency of that wave is <u>288 Hertz</u>

Good Luck!!

Setler79 [48]2 years ago

3 0

Answer:

sadasdsadasd

Explanation:

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3 years ago

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For a specific volume of 0.2 m3/kg, find the quality of steam if the absolute pressure is (a) 40 kPa and (b) 630 kPa. What is th

ICE Princess25 [194]

Answer:

$x=0.0498$

$x'=0.659$

Explanation:

Specific Volume $V=0.2m_3/kg$

Absolute Pressure (a) $P_a= 40kpa$

Giving

$T_a=75.87$

$v_f=1.265*10^{-3}m^3/kg$

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(b) $P_a= 630kpa$

Giving

$T_b=160.13C$

$v_f'=1.10282*10^{-3} m^3/kg$

$v_g'=0.30286 m^3/kg$

(a)

Generally the equation for quality of Steam X is mathematically given by

$x=\frac{v-v_f}{v_g-v_f}$

$x=\frac{0.2-1.0265*10^{-3}}{3.993-1.0265*10^{-3}}$

$x=0.0498$

(b)

Generally the equation for quality of Steam X is mathematically given by

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3 years ago

The free-fall acceleration on Mars is 3.7 m/s^2. What length of pendulum has a period of 1.0 s on Earth? What length of pendulum

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Answer:

Explanation:

Given

Free fall acceleration on mars $g_{m}=3.7\ m/s^2$

Time Period of pendulum on earth $T=1\ s$

Time period of Pendulum is given by

$T=2\pi \sqrt{\frac{L}{g}}$

for earth

$1=2\pi\cdot \sqrt{\frac{L}{9.8}}$

$L=\frac{9.8}{(2\pi )^2}$

$L=0.498\ m$

(b)For same time period on mars length is given by

$L'=\frac{g_m}{(2\pi )^2}$

$L'=\frac{3.7}{39.48}$

$L'=0.0936\ m$

$L'=9.36\ cm$

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3 years ago

Why is the unit of momentum called derived unit

Mnenie [13.5K]

Answer:

the SI unit of momentum is :- kg.ms-1

and we know that,

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E=p2/2m

p=(2Em)1/2

so the derived units are (J.kg)1/2

Explanation:

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3 years ago

How much power is needed to lift a 20-kg object to a height of 4.0 m in 2.5 seconds?

4vir4ik [10]

Answer:

313.92w

Explanation:

Formula for power:

P=W/∆t = Fv

Givens:

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a=9.81m/s²

In order to find power, we first need to solve for work.

W=Fd (force*displacement), f=mg

W=mg∆y

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W=784.8J

P=W/∆t

P=784.8J/2.5s

P=313.92 watts

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3 years ago