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Black_prince [1.1K]
3 years ago
10

Which situation describes the highest rate of power?

Physics
1 answer:
Darya [45]3 years ago
8 0

Answer : The correct option is, (D) A machine does 400 joules of work in 5 seconds.

Explanation :

Power : It is defined a the rate of doing work per unit time.

Formula used :

P=\frac{w}{t}

where,

P = power

w = work done

t = time

Now we have to determine the rate of power for the following options.

(A) A machine does 200 joules of work in 10 seconds.

P=\frac{200}{10}=20W

(B) A machine does 400 joules of work in 10 seconds.

 P=\frac{400}{10}=40W

(C) A machine does 200 joules of work in 5 seconds.

 P=\frac{200}{5}=40W

(D) A machine does 400 joules of work in 5 seconds.

P=\frac{400}{5}=80W

From this we conclude that, a machine does 400 joules of work in 5 seconds has the highest rate of power.

Hence, the correct option is, (D)

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If he feels the chances of low, normal, and high precipitation are 30 percent, 20 percent, and 50 percent respectively, What is
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Question:

The operations manager for a well-drilling company must recommend whether to build a new facility, expand his existing one, or do nothing. He estimates that long-run profits (in $000) will vary with the amount of precipitation (rainfall) as follows:

Alternative             Precipitation                                

                        Low                Normal                 High

Do nothing    -100                       100                    300

Expand           350                       500                   200

Build new       750                       300                    0

If he feels the chances of low, normal, and high precipitation are 30 percent, 20 percent, and 50 percent respectively, What is EVPI (Expected value of Perfect Information)?

A. $140,000

B. $170,000

C. $285,000

D. $305,000

E. $475,000

Answer:

D. $170,000

Explanation:

The expected long run profits are  for

                        Low                Normal                 High

Do nothing    -100*0.3                100*0.2                   300*0.5 = 140

Expand           350*0.3                500*0.2                  200*0.5 = 305

Build new       750*0.3                300*0.2                  0*0.5    = 285

Therefore the expected long run profits are

$140,000

$305,000

$285,000

Based on his selected option being either to build new or to expand, the most profitable option is to expand

=$305,000

EVPI = EPPI-EMV =$170,000

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