Carmen ran one mile in 7 minutes. At this rate, how long will it take her to run 5 miles?

An owner of Honda City car sells his car at a price of RM 7.50,000 with a loss present of 12.5%. Then find the price at which he

Mars2501 [29]

Answer:

Cost = RM 857143

Loss = RM 107143

Step-by-step explanation:

Given:

Selling price SP = RM 750000
Loss% = 12.5
Cost price CP = x

Cost price is found as:

SP = CP - 12.5%
750000 = x - 12.5%
750000= x*(100-12.5)/100
750000= 0.875x
x= 750000/0.875
x≈ RM 857143

Loss is:

RM 857143 - 750000 = RM 107143

8 0

3 years ago

Help, I don’t know how to solve this.

NNADVOKAT [17]

Answer: Angles ABD and BAD (B)

Step-by-step explanation: Angles ABD BAD are not congruent angles, since they are the same angles.

Congruent angles are angles that both measure the same in degrees.

In this case, B is your correct answer since that answer has the same angle and not comparing any 2 angles, just the same one.

Hope This Helped, Have A Great Day!

3 0

2 years ago

The original price of an audio jukebox was 280 it is on sale for 220 what percent discount does this represent

solong [7]

Answer:

The answer would be 12%

Step-by-step explanation:

250-220=30 and 30 is 12% of 250

4 0

2 years ago

Read 2 more answers

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago

The perimeter of Suzanne's rectangular garden is 40 yards. The length of the garden is 12 yards. What is the area of Suzanne's g

asambeis [7]

Answer:

96 sq yards

Step-by-step explanation:

40-24 is 16, and 16/2 is 8. 8 is the second length, so 8 times 12 is 96 which is the area

5 0

3 years ago