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ira [324]
2 years ago
10

Determine the number o( bonding electrons and the number of nonbonding electrons in the structure of CO_2. Enter the number of b

onding electrons followed by the number of nonbonding electrons in the dot structure of this molecule separated by a comma (e.g., 1,2). Draw the main Lewis structure of NOF. Draw nonbonding electrons using the dot notation and bonding electrons as a bond. Determine the number of bonding electrons and the number of nonbonding electrons m the structure of BeF_2. Enter the number of bonding electrons followed by the number of nonbonding electrons, separated by a comma, In the dot structure of this molecule (e.g., 1,2).

Chemistry
1 answer:
Rom4ik [11]2 years ago
7 0

NOF (6,12)

CO2 (8,8)

BeF (4,12)

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Given the Henry’s law constant for O2(4.34*109Pa) at 25° C, calculate the molar concentration of oxygen in air-saturated and O2s
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This is an incomplete question, here is a complete question.

The Henry's law constant for oxygen dissolved in water is 4.34 × 10⁹ g/L.Pa at 25⁰C.If the partial pressure of oxygen in air is 0.2 atm, under atmospheric conditions, calculate the molar concentration of oxygen in air-saturated and oxygen saturated water.

Answer : The molar concentration of oxygen is, 2.67\times 10^2mol/L

Explanation :

As we know that,

C_{O_2}=k_H\times p_{O_2}

where,

C_{O_2} = molar solubility of O_2 = ?

p_{O_2} = partial pressure of O_2 = 0.2 atm  = 1.97×10⁻⁶ Pa

k_H = Henry's law constant  = 4.34 × 10⁹ g/L.Pa

Now put all the given values in the above formula, we get:

C_{O_2}=(4.34\times 10^9g/L.Pa)\times (1.97\times 10^{-6}Pa)

C_{O_2}=8.55\times 10^3g/L

Now we have to molar concentration of oxygen.

Molar concentration of oxygen = \frac{8.55\times 10^3g/L}{32g/mol}=2.67\times 10^2mol/L

Therefore, the molar concentration of oxygen is, 2.67\times 10^2mol/L

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3 years ago
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2 years ago
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? Answer the question below. Type your response in the space provided. What volume of a 2.5 M stock solution of acetic acid (HC2
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Data: 
M_{concentrated} = 2.5\:mol
V_{concentrated} = ?
M_{dilute} = 0.50\:mol
V_{dilute} = 100\:mL\to0.100\:L
<span>
Formula: Dilution Calculations

</span>M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
<span>
Solving:

</span>
M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
2.5 * V_{concentrated} = 0.50 * 0.100
2.5V_{concentrated} = 0.05
V_{concentrated} =  \frac{0.05}{2.5}
\boxed{\boxed{V_{concentrated} = 0.02\:L\:or\:20\:mL}} \end{array}}\qquad\quad\checkmark<span>







</span>
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