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ira [324]
2 years ago
10

Determine the number o( bonding electrons and the number of nonbonding electrons in the structure of CO_2. Enter the number of b

onding electrons followed by the number of nonbonding electrons in the dot structure of this molecule separated by a comma (e.g., 1,2). Draw the main Lewis structure of NOF. Draw nonbonding electrons using the dot notation and bonding electrons as a bond. Determine the number of bonding electrons and the number of nonbonding electrons m the structure of BeF_2. Enter the number of bonding electrons followed by the number of nonbonding electrons, separated by a comma, In the dot structure of this molecule (e.g., 1,2).

Chemistry
1 answer:
Rom4ik [11]2 years ago
7 0

NOF (6,12)

CO2 (8,8)

BeF (4,12)

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I don't need to know why i just want the awnser
Lubov Fominskaja [6]

Answer:

I remember doing this in 7th,

1. D

2. B or D, more leaning on B though

3. A

4 0
3 years ago
The density of water is 1.0gcm3 at 4∘C. What is the mass of 15mL of water at this temperature?
muminat

Answer:

15 gram

Explanation:

in one liter

=1000ml = 1000 cm3

so 15 ml = 15 cm3

15 cm3 = 15 gram

6 0
3 years ago
How much heat is required to change the temperature of a 15 g aluminum can with 100 g of water from 24.5°C to 55°C?
Assoli18 [71]
Heat capacity of aluminium = 0.900 J/g°C
While heat capacity of water = 4.186 J/g°C
Heat = heat gained by water + heat gained by aluminium 
Heat gained by water = 100 × 4.186 × 30.5 
                                   = 12767.3 Joules
Heat gained by aluminium = 15 × 0.9 × 30.5 
                                          = 411.75 Joules
Heat required = 13179.05 Joules or 13.179 kJoules
3 0
2 years ago
The speed of light_____ meters per second
xz_007 [3.2K]

☛ <u>299,792,458</u> meters per second.

4 0
3 years ago
Cobalt-63 has a half-life of 5.3 years. If a pellet that has been in storage for 15.9 years contains 40.0g of Cobalt-63, how muc
Cerrena [4.2K]

Answer:

320 g  

Step-by-step explanation:

The half-life of Co-63 (5.3 yr) is the time it takes for half of it to decay.  

After one half-life, half (50 %) of the original amount will remain.  

After a second half-life, half of that amount (25 %) will remain, and so on.  

We can construct a table as follows:  

  No. of               Fraction         Mass

half-lives   t/yr   Remaining   Remaining/g

      0        0              1

      1         5.3           ½

     2        10.6           ¼

     3        15.9           ⅛                 40.0

     4        21.2           ¹/₁₆

We see that 40.0 g remain after three half-lives.

This is one-eighth of the original mass.

The mass of the original sample was 8 × 40 g = 320 g

5 0
3 years ago
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