Answer:
Mass = 53.45 g
Explanation:
Given data:
Mass of propane = 200 g
Mass of S₂ = 75 g
Theoretical yield /Mass of CS₂ = ?
Solution:
Balanced Chemical equation:
C₃H₈ + 5S₂ → 4H₂S + 3CS₂
Number of moles of propane:
Number of moles = mass / molar mass
Number of moles = 200 g/ 44.1 g/mol
Number of moles = 4.54 mol
Number of moles of S₂:
Number of moles = mass / molar mass
Number of moles = 75 g/ 64.14 g/mol
Number of moles = 1.17 mol
Now we will compare the moles of carbon disulfide with both reactant.
S₂ : CS₂
5 : 3
1.17 : 3/5×1.17 = 0.702
C₃H₈ : CS₂
1 : 3
4.54 : 3×4.54 = 13.62 mol
Number of moles of CS₂ produced by S₂ are less so it will limiting reactant and limit the yield of carbon disulfide.
Theoretical yield of carbon disulfide.
Mass = number of moles ×molar mass
Mass = 0.702 mol × 76.14 g/mol
Mass = 53.45 g
Answer:
7.2
Explanation:
you first have to find the number of moles of nitrogen dioxide by using the number of moles for calcium nitrate and the mole to mole ratios
number of moles of calcium nitrate=mass/mm
=16.4/102
=0.16g/mol
then you use the mole to mole ratios
2 : 4
0.16: x
2x/2=0.64/2
x=0.32g/moles of nitrogen dioxide
then you use the formula for the volume
v=22.4n
=22.4×0.32
=7.2
I hope this helps
<u>Answer:</u> The temperature of the system is 273 K
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
Given mass of carbon dioxide = 1 lb = 453.6 g (Conversion factor: 1 lb = 453.6 g)
Molar mass of carbon dioxide = 44 g/mol
Putting values in above equation, we get:
To calculate the temperature of gas, we use the equation given by ideal gas equation:
PV = nRT
where,
P = Pressure of carbon dioxide = 200 psia = 13.6 atm (Conversion factor: 1 psia = 0.068 atm)
V = Volume of carbon dioxide = 
(Conversion factor: 
)
n = number of moles of carbon dioxide = 10.31 mol
R = Gas constant = 
T = temperature of the system = ?
Putting values in above equation, we get:
Hence, the temperature of the system is 273 K
