Answer:
it is a membrane-linked glycoproteins that connects with other cells which are also called transmembrane
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<h3>
Answer:</h3>
0.95 atm
<h3>
Explanation:</h3>
We are given;
Initial pressure, P1 = 1.0 atm
Initial temperature, T1 =298 K (25°C + 273)
Initial volume, V1 = 0.985 L
Final temperature, T2 = 295 K (22°C + 273)
Final volume, V2 = 1.030 L
We are required to find final air pressure;
Using the combined gas law;
![\frac{P1V1}{T1} =\frac{P2V2}{T2}](https://tex.z-dn.net/?f=%5Cfrac%7BP1V1%7D%7BT1%7D%20%3D%5Cfrac%7BP2V2%7D%7BT2%7D)
To get, P2 ;
![P2=\frac{P1V1T2}{T1V2}](https://tex.z-dn.net/?f=P2%3D%5Cfrac%7BP1V1T2%7D%7BT1V2%7D)
![P2=\frac{(1.0)(0.985L)(295)}{(1.030)(298)}](https://tex.z-dn.net/?f=P2%3D%5Cfrac%7B%281.0%29%280.985L%29%28295%29%7D%7B%281.030%29%28298%29%7D)
![P2 = 0.947 atm](https://tex.z-dn.net/?f=P2%20%3D%200.947%20atm)
= 0.95 atm
Therefore, the air pressure at the top of the mountain is 0.95 atm
What that question makes 0 sense and there is no picture