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JulijaS [17]
3 years ago
7

If you have a 100g of Boron and you want to find out how

Chemistry
1 answer:
Dmitry [639]3 years ago
7 0

Answer:

5.57 x 10^24 atoms

Explanation:

first, you are seeking the number of ATOMS of Boron.

Boron has an Atomic mass of 10.8 g/mol (see #5 on the periodic table)

100 gm of Boron would have 100 g /10.8 g/mol =9.26 moles

each mole has Avogadros number of atoms 6.02 x 10^23

9.26 moles has 9.26 x 6.02 x 10^23 atoms =5.57 x 10^24 atoms

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A certain chemical reaction releases 36.2 kJ/g of heat for each gram of reactant consumed. How can you calculate what mass of re
Lilit [14]

Answer:

0.038 g of reactant

Explanation:

Data given:

Heat release for each gram of reactant consumption = 36.2 kJ/g

mass of reactant that release 1360 J of heat = ?

Solution:

As  36.2 kJ of heat release per gram of reactant consumption so first we will convert KJ to J

As we know

1 KJ = 1000 J

So

36.2 kJ = 36.2 x 1000 = 36200 J

So it means that in chemical reaction 36200 J of heat release for each gram of reactant consumed so how much mass of reactant will be consumed if 1360 J heat will release

Apply unity formula

                 36200 J of heat release ≅ 1 gram of reactant

                 1360 J of heat release ≅ X gram of reactant

Do cross multiplication

              X gram of reactant = 1 g x 1360 J / 36200 J

              X gram of reactant = 0.038 g

So 0.038 g of reactant will produce 1360 J of heat.

5 0
3 years ago
The average dosage of oxcarbazepine for an epileptic child between the ages of 4 and 16 is 9.00 mg per 1 kg of body weight (9.00
melamori03 [73]
Convert the child weight (37.3 pounds) to kilograms

37.3 lb x 0.453 kg /1lb = "A kg"

multiply the dose (9.00mg/kg) by the weight of the child to find how much you need to give him

A kg * 9.00 mg/1kg = "B mg" 

calculate the mL of suspension dividing the "B mg" by the concentration of the suspension 60.0 mg/mL

B mg * 1mL/ 60.0 mg = C mL <span>oxcarbazepine</span>
8 0
3 years ago
Read 2 more answers
What volume of a 0.33-M C12H22O11 solution can be diluted to prepare 25 mL of a solution with a concentration of 0.025 M?
Vsevolod [243]

The dilution formula can be used to find the volume needed

c1v1 = c2v2

Where c1 is concentration and v1 is volume of the concentrated solution

And c2 is concentration and v2 is volume of the diluted solution to be prepared

c1 - 0.33 M

c2 - 0.025 M

v2 - 25 mL

Substituting these values in the equation

0.33 M x v1 = 0.025 M x 25 mL

v1 = 1.89 mL

Therefore 1.89 mL of the 0.33 M solution needs to be diluted up to 25 mL to make a 0.025 M solution

7 0
3 years ago
Write the electron configuration (ground and excited states) for element with atomic number 16 ?
Talja [164]
2, 8,6 because it has to be in a configuration of 2,8,8
3 0
3 years ago
Energy is just like any other chemical or physical process, where it cannot be created or destroyed. Which Law states this fact?
Ganezh [65]

Answer:

Law of Conservation of Energy

Explanation:

5 0
3 years ago
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