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JulijaS [17]
3 years ago
7

If you have a 100g of Boron and you want to find out how

Chemistry
1 answer:
Dmitry [639]3 years ago
7 0

Answer:

5.57 x 10^24 atoms

Explanation:

first, you are seeking the number of ATOMS of Boron.

Boron has an Atomic mass of 10.8 g/mol (see #5 on the periodic table)

100 gm of Boron would have 100 g /10.8 g/mol =9.26 moles

each mole has Avogadros number of atoms 6.02 x 10^23

9.26 moles has 9.26 x 6.02 x 10^23 atoms =5.57 x 10^24 atoms

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In the PhET simulation window, click the radio button labeled Mystery in the Blocks menu on the right-hand side of the screen. U
Yuliya22 [10]

Answer:

B, D, E, C, A

Explanation:

We have 5 blocks with their respective masses and volumes.

Block            Mass            Volume

  A                65.14 kg       103.38 L

  B                0.64 kg         100.64 L

  C                4.08 kg         104.08 L

  D                3.10 kg          103.10 L

  E                 3.53 kg         101.00 L

The density (ρ) is an intensive property resulting from dividing the mass (m) by the volume (V), that is, ρ = m / V

ρA = 65.14 kg / 103.38 L = 0.6301 kg/L

ρB = 0.64 kg / 100.64 L = 0.0064 kg/L

ρC = 4.08 kg / 104.08 L = 0.0392 kg/L

ρD = 3.10 kg / 103.10 L = 0.0301 kg/L

ρE = 3.53 kg / 101.00 L = 0.0350 kg/L

The order from least dense to most dense is B, D, E, C, A

4 0
3 years ago
How did the germ theory of disease become an accepted idea?
umka21 [38]
<span>The answer is:
The work of three scientists brought about scientific consensus.
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5 0
4 years ago
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a balloon contains 0.950 of nitrogen gas at a volume of 25.5 L. How many grams of N2 should be released from the balloon to brin
son4ous [18]

Answer:

4.27 g

Explanation:

We can write that for a gas kept at constant pressure and temperature, the number of moles of the gas is directly proportional to its volume:

n\propto V

Which can be rewritten as

\frac{n_1}{V_1}=\frac{n_2}{V_2}

where here we have:

n_1=0.950 mol is the initial number of moles

V_1=25.5 L is the initial volume of the gas

V_2=17.3 L is the final volume of the gas

So the final number of moles is

n_2=\frac{n_1 V_2}{V_1}=\frac{(0.950)(17.3)}{25.5}=0.645 mol

So the number of moles that should be released from the balloon is:

\Delta n = n_1-n_2=0.950-0.645=0.305 mol

The molar mass of gas N2 is

M=14 g/mol

Therefore, the mass of gas that should be released is:

\Delta m = M\Delta n =(14.0)(0.305)=4.27 g

4 0
4 years ago
Which of the following describes the stage that occurs after condensation in the water cycle?
NISA [10]

Answer:

Precipitation

Explanation:

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Answer:

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