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vesna_86 [32]
3 years ago
10

A gas has a volume of 8.21 mL and exerts a pressure of 2.9 atm. What new volume will the gas have if the pressure is changed to

4.0 atm.
Physics
1 answer:
labwork [276]3 years ago
3 0

Answer:

5.95 ml

Explanation:

Given info

P1=2.9 atm

V1=8.21 ml

P2=4 atm

From Boyle's law we know that p1v1=p2v2 where p and v are pressure and volume respectively. This is at a constant temperature. Making v2 the subject of formula then

V2=p1v1/p2

V2= 2.9*8.21/4=5.95 ml

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A quantity of a gas has an absolute pressure of 400 kPa and an absolute temperature of 110 degrees kelvin. When the temperature
shepuryov [24]

You can make sure there's no change in volume by keeping
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You have a 3.00-liter container filled with N₂ at 25°C and 4.45 atm pressure connected to a 2.00-liter container filled with Ar
LuckyWell [14K]

Answer : The final pressure in the two containers is, 2.62 atm

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

Thus, the expression for final pressure in the two containers will be:

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P=\frac{P_1V_1+P_2V_2}{V}

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P_2 = pressure of Ar gas = 2.75 atm

V_1 = volume of N₂ gas = 3.00 L

V_2 = volume of Ar gas = 2.00 L

P = final pressure of gas = ?

V = final volume of gas = (4.45 + 2.75) L = 7.2 L

Now put all the given values in the above equation, we get:

P=\frac{(4.45atm)\times (3.00L)+(2.75atm)\times (2.00L)}{7.2L}

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Thus, the final pressure in the two containers is, 2.62 atm

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