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o-na [289]
4 years ago
8

The speed of a boat undergoing constant acceleration increases from 5 meters per second to 15 meters per second over a period of

20 seconds. How far does the boat travel during this time?

Physics
1 answer:
defon4 years ago
4 0
Should be 250m. check with your teacher and let me know

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A car initially miving at 0.5m/s along a track.the car come to rest after travelling 1m.the car is repeated on the same of track
cluponka [151]

Answer:

it will travel 69 m long consuming. it is totally wrong

6 0
3 years ago
If u add 1.362 and 25.2 what is the correct answer?
krek1111 [17]

Answer:

26.562

Explanation:

1+25= 26

0.362+0.2= 0.562

26+0.562= 26.562

or just use a calculator

6 0
2 years ago
5.
Kamila [148]

Answer:  (x - 4)² + (y - 7)² = 9

<u>Explanation:</u>

The equation of a circle is: (x - h)² + (y - k)² = r²    where

  • (h, k) is the center
  • r is the radius

Given: (h, k) = (4, 7)

Find the intersection of the given equation and the perpendicular passing through (4, 7).

3x - 4y = -1

     -4y = -3x - 1

        y=\dfrac{3}{4}x-1

              m=\dfrac{3}{4}      -->      m_{\perp}=-\dfrac{4}{3}

y-y_1=m_{\perp}(x-x_1)\\\\y-7=-\dfrac{4}{3}(x-4)\\\\\\y=-\dfrac{4}{3}x+\dfrac{16}{3}+7\\\\\\y=-\dfrac{4}{3}x+\dfrac{37}{3}

Use substitution to find the point of intersection:

x=\dfrac{29}{5}=5.8,\qquad y=\dfrac{23}{5}=4.6

Use the distance formula to find the distance from (4, 7) to (5.8, 4.6) = radius

r=\sqrt{(5.8-4)^2+(4.6-7)^2}\\\\r=\sqrt{3.24+5.76}\\\\r=\sqrt9\\\\r=3

Input h = 4, k = 7, and r = 3 into the circle equation:

(x - 4)² + (y - 7)² = 3²

(x - 4)² + (y - 7)² = 9

4 0
3 years ago
Can please anybody help me my H.W to fill in the blanks​
kozerog [31]
<h3>Hi!</h3>

<h3>The correct answers would be:</h3>

1. Metallic ; Nonmetallic  

2. Radioisotope  

3. Boils

4. Endothermic

5. Kinetic  

6. Alpha Particles

7. Highest

8. Scientific Model

9. Mass Number ; Atomic Number

<h3>Kindly find the explanations in the document attached</h3>
Download docx
8 0
3 years ago
Why must the operating temperature of a heat engine be higher than that of the cold sink?
Anna35 [415]

Answer:

It is important to note, that the 2nd Law of thermodynamics plays no fundamental role in answering this question; we need a heat sink because the entropy is a state function, and at the end of the reversible process (which is visualized through the Carnot cycle diagram relevant for this problem), the entropy value of the system must return to the value it had originally.

6 0
4 years ago
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