Soft of easy help plz B C A D

Which of the following aqueous solution will have the highest boiling point

Sliva [168]

Ionic molecules have higher boiling point than covalent molecules.

So that leaves Na2SO4 and NaCl.

The ionic molecule with higher charge will have higher boiling point.

Na2SO4 have ions with charge +-2.

NaCl have ions with charge +-1.

So the answer is C.

4 0

3 years ago

Which of the following is an experiment?

ValentinkaMS [17]

D! because when you record something you will probably analyze the results and those are two big KEY components of an Experiment!

8 0

3 years ago

Read 2 more answers

Determine the expected diffraction angle for the first-order diffraction from the (111) set of planes for FCC nickel (Ni) when m

faust18 [17]

Answer:

56°

Explanation:

First calculate $a:$

$a=2 R \sqrt{2}=2(0.1246) \sqrt{2}=0.352 \mathrm{nm}$

The interplanar spacing can be calculated from:

$d_{111}=\frac{a}{\sqrt{1^{2}+1^{2}+1^{2}}}=\frac{0.352}{\sqrt{3}}=0.203 \mathrm{nm}$

The diffraction angle is determined from:

$\sin \theta=\frac{n \lambda}{2 d_{111}}=\frac{1(0.1927)}{2(0.2035)}=0.476$

Solve for $\theta$

$\theta=\sin ^{-1}(0.476)=28^{\circ}$

The diffraction angle is:

$2 \theta=2\left(28^{\circ}\right)=56^{\circ}$

4 0

4 years ago

Notice what happens to the numbers of protons, neutrons, and electrons when you

babymother [125]

Answer:

Only the number of neutrons change.

3 0

4 years ago

Use the van der waals equation to calculate the pressure exerted by 1.335 mol of cl2 in a volume of 4.920 l at a temperature of

nika2105 [10]

Van der waal or ideal eqn is given by PV = NRT; P = NRT/ V. Where N = 1.335 is the number of moles. T = 272K is temperature. V = 4.920L is the volume. And R = 0.08205L. Substiting the values into the eqn; we have, P = (1.331* 0.08205 * 272)/ 4.920 = 29.7047/ 4.920 = 6.03atm.

7 0

3 years ago