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Shalnov [3]
3 years ago
15

Find the square root of 25 6 4 5 7

Mathematics
2 answers:
lara31 [8.8K]3 years ago
4 0

Answer:

5 is the answer

............

Bond [772]3 years ago
3 0

Answer:

5

Step-by-step explanation:

What number multiplied by itself gives you 25

5*5 = 25

sqrt(25) = 5

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A growing farming conglomerate increases its water usage at a rate of 10% every year. If it
Elena-2011 [213]

The quantity of water the farming conglomerate would use 17 years from now is 65,708.11.

<h3>What is the amount of water that would be used 17 years from now?</h3>

The formula for calculating the amount of water that would be needed 1 years from now:

FV = P (1 + r)^N

  • FV = Future value
  • P = Present value
  • R = interest rate
  • N = number of years

13000 x 1.1^17 = 65,708.11

To learn more about future value, please check: brainly.com/question/18760477

8 0
2 years ago
A bike ramp is constructed such that a 5-foot launching ramp makes a 30° angle with the ground.
Leni [432]
Whats the answer.......waiting
7 0
3 years ago
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How do you simply 2x+8=-6
photoshop1234 [79]
To simplify <span>2x + 8 = -6, the easiest way is to manipulate the equation one step at a time:

</span>2x + 8 = <span>-6
</span>2x = <span>-14             (subtract 8 from both sides)
</span>x = -7                 (divide both sides by 2)


3 0
3 years ago
What is the limit of f (×) as x approaches - infinty
tatyana61 [14]
If the degree of numerator and denominator are equal, then limit will be leading coefficient of numerator divided by the leading coefficient of denominator.

So then the limit would be 3/1 = 3.

Alternatively,

\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}=\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}\cdot\dfrac{1/x^2}{1/x^2}=\lim_{x\to\infty}\dfrac{3+\frac6{x^2}}{1-\frac4{x^2}} = \dfrac{3+0}{1-0}=\boxed{3}

Hope this helps.
5 0
3 years ago
Which table represents a quadratic relationship?
svp [43]

In each case, the x-values are equally-spaced. Thus looking at second differences will tell you if the relation is quadratic. If the second differences are non-zero and constant, then the values have a quadratic relationship.

A. First differences are 2-4 = -2, 1-2 = -1, 0.5-1 = -0.5. Second differences are -1-(-2) = 1, -0.5-(-1) = 0.5. Since 1 ≠ 0.5, this relation is not quadratic. (It is exponential with a base of 1/2.)

B. First differences are 128-135 = -7, 105-128 = -23, 72-105 = -33. Second differences are -23-(-7) = -16, -33-(-23)=-10. Since -16 ≠ -10, this relation is not quadratic. (It is cubic, since 3rd differences are constant at +4.)

C. First differences are -23.2-(-23.4) = 0.2, -23.0-(-23.2) = 0.2, -22.8-(-23.0) = 0.2. Second differences are zero, so this is not a quadratic relation. (It is linear, with a slope of 0.2.)

D. First differences are 56-90 = -34, 26-56 = -30, 0-26 = -26. Second differences are -30-(-34) = 4, -26-(-30) = 4. These are constant (=4), so the relation is quadratic.

The appropriate choice is ...

... D. x -1 0 1 2 3 4

... f(x) 90 56 26 0 -22 -40

4 0
4 years ago
Read 2 more answers
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