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Ymorist [56]
3 years ago
7

Selenium has six valence electrons. What is the valence of selenium?

Chemistry
1 answer:
viktelen [127]3 years ago
3 0
The six electrons in the outermost shell allow selenium to have a variety of valence numbers.

The valence of selenium depends on which compound it is in. Selenium is very similar to sulfur. It may have a valence of 6.
EXAMPLE:

 selenium hexafluoride SeF6, selenium trioxide SeO3 


May have 4;

example

selenium tetrafluoride SeF4, selenium dioxide SeO2

MAy have 2;
 
example

selenium difluoride SeF2, selenium dichloride SeCl2 

and may have -2;

example

hydrogen selenide H2Se
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The answer would be the 3. Mg + energy--> mg+ + e- 
Ionization Energy is the amount of energy vital to eliminate the most loosely bond electron from an atom in the gas stage. Since Magnesium has a higher first energy which is 738 kj/mol, is the energy needed to remove the outermost, or highest energy.
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3 years ago
Calculate the mass percent of HOCH 2CH 2OH in a solution made by dissolving 3.2 g of HOCH 2CH 2OH in 43.5g of water.
grin007 [14]

Answer:

\%m/m=6.85\%

Explanation:

Hello,

In this case, we are asked to compute the by mass percent for the given 3.2 g of ethylene glycol in 43.5 g of water. In such a way, since the by mass percent is computed as follows:

\%m/m=\frac{m_{solute}}{m_{solute}+m_{solvent}} *100\%

Whereas the solute is the ethylene glycol and the solvent the water, therefore we obtain:

\%m/m=\frac{3.2g}{3.2g+43.5g} *100\%\\\\\%m/m=6.85\%

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5 0
3 years ago
Which of the following lists includes only molecules?
siniylev [52]
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3 years ago
A certain alcohol contains only three elements, carbon, hydrogen, and oxygen. Combustion of a 60.00 gram sample of the alcohol p
marin [14]

Answer:

C_2H_6O

Explanation:

The first step is the <u>calculation of the moles</u> of H_2O and CO_2, so:

114.6~g~CO_2\frac{1~mol~CO_2}{44~g~CO_2}=2.6~mol~of~CO_2

70.44~g~H_2O\frac{1~mol~H_2O}{18~g~H_2O}=~3.9~mol~H_2O

Now, in 1 mol of CO2 we have 1  mol of C and in 1 mol of H_2O we have 1 mol of H. Additionally, if we want to calculate the moles of oxygen we need to <u>calculate the grams of C and O</u> and then do the <u>substraction</u> form the initial amount, so:

2.6~mol~CO_2\frac{1~mol~C}{1~mol~CO_2}\frac{12~g~C}{1~mol~C}=31.25~g~of~C

3.9~mol~H_2O\frac{2~mol~H}{1~mol~H_2O}\frac{1~g~H}{1~mol~H}=7.82~g~of~H

Total~grams=~31.25~+~7.82=39.08~g

grams~of~O=60.00~g-~39.08~g=20.92~g~of~O

Now we can <u>convert the grams</u> of O to moles, so:

20.92~g~of~O\frac{1~mol~O}{16~g~O}=1.30~mol~O

The next step is to divide all the mol values by the <u>smallest one</u>:

O=\frac{1.30~mol~O}{1.30~mol~O}=~1

C=\frac{2.6~mol~C}{1.30~mol~O}=~2

H=\frac{7.82~mol~H}{1.30~mol~O}=6

Therefore the formula is C_2H_6O

6 0
3 years ago
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