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docker41 [41]
3 years ago
11

Calculate the mass percent of HOCH 2CH 2OH in a solution made by dissolving 3.2 g of HOCH 2CH 2OH in 43.5g of water.

Chemistry
1 answer:
grin007 [14]3 years ago
5 0

Answer:

\%m/m=6.85\%

Explanation:

Hello,

In this case, we are asked to compute the by mass percent for the given 3.2 g of ethylene glycol in 43.5 g of water. In such a way, since the by mass percent is computed as follows:

\%m/m=\frac{m_{solute}}{m_{solute}+m_{solvent}} *100\%

Whereas the solute is the ethylene glycol and the solvent the water, therefore we obtain:

\%m/m=\frac{3.2g}{3.2g+43.5g} *100\%\\\\\%m/m=6.85\%

Best regards.

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We need to obtain the number of moles of carbon, hydrogen and oxygen in the compound;

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