Question

You throw a ball straight down from an apartment balcony to the ground below. The ball has an initial velocity of 5.10 m/s, directed downward, and it hits the ground 1.92 s after it is released. Find the height of the balcony.

Answer 1

Answer:

the height of the balcony from where the ball is thrown is 27.874 m.

Explanation:

given,

initial velocity (u) = 5.1 m/s

time (t) = 1.92 s

height of balcony = ?

using equation;          

$s = u t + \dfrac{1}{2} at^2$

$h =5.1 \times 1.92 + \dfrac{1}{2}\times 9.81\times 1.92^2$

h= 9.792 + 18.082                      

h = 27.874 m

hence, the height of the balcony from where the ball is thrown is 27.874 m.