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Annette [7]
4 years ago
9

Solar panels are rated by their theoretical maximum output capacity. A 2-kW PV panel would theoretically produce 2 kW of electri

city at its maximum output (during peak solar radiance). If the average daily peak sun-hour in Philadelphia are approximately 4.0 hour and a rowhome is outfitted with 10 PV panels each having a capacity of 260 W, how much energy (kilowatt x hours) would be generated in one year (in units of kWh / year)?
Physics
1 answer:
Anastaziya [24]4 years ago
7 0

Answer:

3796 KWh per year.

Explanation:

Since, we have considered theoretical maximum output during peak solar radiance which is 4 hours every day.

So, 10 PV panels each of 260 W capacity will produce

260×10= 2600 W of electricity at its maximum output.

2600 W @ 4 hours

Energy in  KWh = \frac{2600\times4}{1000}= 10.4 KWh

Therefore,  everyday we get 10.4 KWh of electricity at 4 hours peak solar radiance.

So, energy generated for 1 year= 10.4×365= 3796 KWh

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Niobium metal becomes a superconductor when cooled below 9K. Itssuperconductivity is destroyed when the surface magnetic fieldex
elena-14-01-66 [18.8K]

Answer:

the maximum current is 500 A

Explanation:

Given the data in the question;

the B field magnitude on the surface of the wire is;

B = μ₀i / 2πr

we are to determine the maximum current so we rearrange to find i

B2πr = μ₀i

i = B2πr / μ₀

given that;

diameter d = 2 mm = 0.002 m

radius = 0.002 / 2 = 0.001 m

B = 0.100 T

we know that permeability; μ₀ = 4π × 10⁻⁷ Tm/A

so we substitute

i = (0.100)(2π×0.001 ) / 4π × 10⁻⁷

i = 500 A

Therefore, the maximum current is 500 A

4 0
3 years ago
A mass of 0.75 kilograms is attached to a spring/mass oscillator. A force of 5 newtons is required to stretch the spring 0.5 met
zlopas [31]

Answer:

b > 66.41 kg/s

Explanation:

The spring force F = -kx, where k = spring constant, the damping force f = -bv. The net force F' = F + f

F + f = ma

-kx - bv = ma

-kx -bdx/dt = md²x/dt².

Re-arranging the equation, we have

So, md²x/dt² + bdx/dt + kx = 0

Dividing through by m, we have

d²x/dt² + (b/m)dx/dt + (k/m)x = 0

This is a second-order differential equation. The characteristic equation is thus,

D² + (b/m)D + (k/m) = 0

Using the quadratic formula, we find D.

D = \frac{-(b/m) +/- \sqrt{(b/m)^{2} - 4k/m} }{2}

For an overdamped system,

(b/m)^{2} - 4k/m} >   0

(b/m)^{2} >   4k/m}\\(b/m) >   \sqrt{4k/m}} \\(b/m) >   2\sqrt{k/m}} \\b >   2\sqrt{km}}

Now, k = F/x. Since the weight of the object causes the spring to stretch a distance of 0.5 m, k = mg/x where m = mass of object = 0.75 kg, g = 9.8 m/s² and x = x₀ =0.5 m.

Substituting k = mg/x into the inequality for b, we have

b > 2√{(mg/x₀)m}

b > 2√{(m²g/x₀)}

b > 2m√{g/x₀)}

b > 2 × 0.75 kg√{9.8 m/s²/0.5 m)}

b > 1.5 kg√{19.6/s²)}

b > 1.5 kg × 4.427/s

b > 66.41 kg/s

6 0
3 years ago
People under going physical therapy after an injury often find it helpful to perform exercise in water? Why?
BARSIC [14]
Because water puts less weight on the joints helping prevent more pain and potentially problems

Also if you could give me Brainily that would be amazing
7 0
3 years ago
What percentage of the earth's mass is the moon's mass?
Schach [20]

Answer:

ssssssssss

Explanation:

hshjdjjfjjjjhhddd

5 0
3 years ago
Steam is leaving a 4-L pressure cooker whose operating pressure is 150 kPa. It is observed that the amount of liquid in the cook
Anna71 [15]

Answer:

The mass flow rate is 2.37*10^-4kg/s

The exit velocity is 34.3m/s

The total flow of energy is 0.583 KJ/KgThe rate at which energy leave the cooker is 0.638KW

<u></u>

7 0
2 years ago
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