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2 years ago

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A child standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down, the child conti

nues moving forward at the original speed. This is an example of

2 answers:

expeople1 [14]2 years ago

3 0

Newton's first law of motion

dlinn [17]2 years ago

3 0

The best answer would be, <u><em>Newton's first law of motion. </em></u>

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What is the difference between tangential acceleration and centripetal acceleration?

Nuetrik [128]

Centripetal acceleration is directed along a radius so it may also be called the radial acceleration. If the speed is not constant, then there is also a tangential acceleration (at). The tangential acceleration is, indeed, tangent to the path of the particle's motion.

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2 years ago

Julio hit a baseball. What caused the ball to change direction at the time of impact?

WARRIOR [948]

The answer is c. the force of his swing

At the time of the impact, there is a collision between two bodies moving in opposite directions.

The force exerted on the ball causes the change of velocity.

7 0

2 years ago

Read 2 more answers

A fast-food restaurant uses a conveyor belt to send the burgers through a grilling machine. if the grilling machine is 1.2 m lon

Vinil7 [7]

length of the grilling machine is 1.2 m

time taken to cook the burger is 2.7 min = 162 s

so the speed of the machine should be like this that if must have to cook till it cross the machine

$v = \frac{d}{t}$

$v = \frac{1.2}{162}$

$v = 7.41* 10^{-3} m/s$

now in one minute the total length of the machine that is covered is given by

$L = v*t$

$L = 7.41*10^{-3}* 60 = 44.4 cm$

now distance between the burgers is 15 cm

so total production rate will be

$N = \frac{44.4}{15} = 3 burger/min$

so it will produce 3 burger per minute

8 0

3 years ago

Two toy cars (m1 = 0.200 kg and m2 = 0.250 kg) are held together rear to rear with a compressed spring between them. When they a

timurjin [86]

Answer:

Acceleration of the second particle at that moment is given as

$a_2 = 2.12 m/s^2$

Explanation:

As we know that both cars are connected by same spring

So on this system of two cars there is no external force

So we will have

$F = 0 = m_1a_1 + m_2a_2$

now we have

$m_1 = 0.200 kg$

$m_2 = 0.250 kg$

$a_1 = 2.65 m/s^2$

now we have

$0.200(2.65) + 0.250a_2 = 0$

so we have

$a_2 = 2.12 m/s^2$

8 0

3 years ago

The surface charge density on an infinite charged plane is - 2.10 ×10−6C/m2. A proton is shot straight away from the plane at 2.

inn [45]

Explanation:

Formula to calculate electric field because of the plate is as follows.

E = $\frac{\sigma}{2 \times \epsilon_{o}}$

= $\frac{2.10 \times 10^{-6}}{2 \times 8.85 \times 10^{-12}}$

= $1.18 \times 10^{5} N/C$

Now, we will consider that equilibrium of forces are present there. So,

ma = qE

a = $\frac{1.6 \times 10^{-19} \times 1.18 \times 10^{5}}{1.67 \times 10^{-27}}$

= $1.13 \times 10^{13} m/s^2$

According to the third equation of motion,

$v^{2} = 2 \times a \times d$

or, d = $\frac{v^{2}}{2d}$

= $\frac{(2.4 \times 10^{6})^{2}}{2 \times 1.13 \times 10^{13}}$

= 0.254 m

Thus, we can conclude that the proton will travel 0.254 m before reaching its turning point.

7 0

2 years ago