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MAVERICK [17]
3 years ago
13

The length of a rectangle is 3 yd longer than its width if the perimeter is 42 yd find the area

Mathematics
1 answer:
pogonyaev3 years ago
4 0

14 yd

42 \div 3

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The length of a rectangle is five times its width. if the perimeter of the rectangle is 96 yd , find its area.
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Rectangle has 4 sides dived 96 by 4 and then from there you have to make length be bigger than width
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I WILL GIVE BRAINLIEST FOR Correct Answer
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Part A) Find BC, the distance from Tower 2 to the plane, to the nearest foot.

in the triangle ACD
sin16=CD/(7600+BD)--------> CD=sin16*(7600+BD)---------> equation 1 

in the triangle BCD
sin24=CD/BD-----------> CD=sin24*BD---------------> equation 2
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sin16*(7600+BD)=sin24*BD-----> sin16*7600+sin16*BD=sin24*BD
sin24*BD-sin16*BD=sin16*7600----> BD=[sin16*7600]/[sin24-sin16]
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in the triangle BCD
cos24=BD/BC---------> BC=BD/cos24-------> 15979/cos24-------> 17491
BC=17491 ft

the answer part 1) BC is 17491 ft

Part 2) Find CD, the height of the plane from the ground, to the nearest foot.

CD=sin24*BD        ( remember equation 2)
BD=15979 ft
CD=sin24*15979 -----------> CD=6499 ft

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Area of part 1:A1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2Area of part 2:A2=length*width=(8+2)*1=10 ft2Area of part 3:A3=length*width=8*2=16 ft2
Total shaded area : A1+A2+A3=41 ft2Total area of the reactangle : A=16*8=128 ft2Total area of the nonshaded region : 128-41=87 ft2

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3 years ago
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