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Akimi4 [234]
3 years ago
14

Students performed several trials using the laboratory setup shown.

Physics
1 answer:
Alex777 [14]3 years ago
3 0

The roughness of the surface should be varied by the students tp test the hypothesis in the best possible way.

Explanation:

As the hypothesis stated the relation between roughness of the surface and the distance covered by the marble, students first need to find the independent variable among these two. The independent variable will be the one which will not depend on the result of the other variable. But there will be change in the dependent variable on changing the independent variable.

So here the independent variable is the roughness of the surface as per the hypothesis. And the dependent variable will be distance covered by the marble.

So the students should vary the independent variable and check for desired changes in the dependent variable for confirmation of hypothesis.

Thus, the roughness of the surface should be varied by the students tp test the hypothesis in the best possible way.

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Hello!

\large\boxed{KE = 360 J}

Use the equation KE = 1/2mv² to solve for the kinetic energy of the man.

We are given the mass and velocity, so plug these values into the equation:

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To solve this problem it is necessary to apply the concepts related to the Gravitational Force, for this purpose it is understood that the gravitational force is described as

F_g = \frac{Gm_1m_2}{r^2}

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G = Gravitational Universal Force

m_i = Mass of each object

To solve this problem it is necessary to divide the gravitational force (x, y) into the required components and then use the tangent to find the angle generated between both components.

Our values are given as,

m_1 =4.6 kg\\m_2 = 7.2 kg\\m_3 = 2.6 kg\\r_1 = 5.7 m\\r_2 = 4.2 m

Applying the previous equation at X-Axis,

F_x = \frac{Gm_1m_3}{R_{1}^2}\\F_x = \frac{6.67*10^{-11}*4.6*2.6}{5.7^2}\\F_x = 2.46*10^{-11}N

Applying the previous equation at Y-Axis,

F_y = \frac{Gm_2m_3}{R_2^2}\\F_y = \frac{6.67*10^{-11}*7.2*2.6}{4.2^2}\\F_y = 7.08*10^{-11} N

Therefore the angle can be calculated as,

tan\theta = \frac{F_y}{F_x}\\\theta = tan^{-1} \frac{F_y}{F_x}\\\theta = tan^{-1} \frac{7.08*10^{-11}}{2.46*10^{-11}}\\\theta = 71\°

Then in the measure contrary to the hands of the clock the Force in the particle 3 is in between the positive direction of the X and the negative direction of the Y at 71 ° from the positive x-axis.

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