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3 years ago

Students performed several trials using the laboratory setup shown.

Physics

1 answer:

Alex777 [14]3 years ago

3 0

The roughness of the surface should be varied by the students tp test the hypothesis in the best possible way.

Explanation:

As the hypothesis stated the relation between roughness of the surface and the distance covered by the marble, students first need to find the independent variable among these two. The independent variable will be the one which will not depend on the result of the other variable. But there will be change in the dependent variable on changing the independent variable.

So here the independent variable is the roughness of the surface as per the hypothesis. And the dependent variable will be distance covered by the marble.

So the students should vary the independent variable and check for desired changes in the dependent variable for confirmation of hypothesis.

Thus, the roughness of the surface should be varied by the students tp test the hypothesis in the best possible way.

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While standing on an open bed of a truck moving at 35 m/s, an archer sees a duck flying directly overhead. The archer shoots an

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Answer:

Part a)

$t = 20 s$

Part b)

$x = 700 m$

Part c)

Since horizontal speed of truck and the arrow is same so the arrow will strike at the position of the archer as they both moving with same speed

Explanation:

Part a)

As we know that the arrow moves with uniform acceleration in vertical direction so we can use kinematics in Y direction

Here we know that

$\Delta y = v_y t + \frac{1}{2}at^2$

since the arrow lands at the same height so its vertical displacement of whole motion is zero

so we will have

$0 = 98 t - \frac{1}{2}(9.8) t^2$

$0 = 98 t - 4.9 t^2$

$t = 20 s$

Part b)

Horizontal distance moved by the arrow

$x = v_x t$

here horizontal speed of arrow is same as that of speed of truck

so we will have

$x = 35 \times 20$

$x = 700 m$

Part c)

Since horizontal speed of truck and the arrow is same so the arrow will strike at the position of the archer as they both moving with same speed

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3 years ago

In which atmosphere layer does 80 percent of the gas in the atmosphere reside?

VladimirAG [237]

Answer: TheTroposphere contains 80% of the total gas in the atmosphere

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3 years ago

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In Case 1, a mass M hangs from a vertical spring having spring constant k and is at rest in its equilibrium position. In Case 2

evablogger [386]

Answer: hello your question is incomplete attached below is the complete question

answer : 1/2 KD^2 ( option A )

Explanation:

P.E ( potential energy ) = mgd

In case 1 P.E = 0 i.e. mgd = 0

Given that in case 2 the Mass M had moved through the Distance D by the compression of the spring

The potential energy of the M in case 2

= P.E of M at rest + P.E of the spring

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3 years ago

A wire of resistance R is cut into ten equal parts which are then connected in parallel. The equivalent resistance of the combin

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Answer:

The equivalent resistance of the combination is R/100

Explanation:

Electric Resistance

The electric resistance of a wire is directly proportional to its length. If a wire of resistance R is cut into 10 equal parts, then each part has a resistance of R/10.

Parallel connection of resistances: If R1, R2, R3,...., Rn are connected in parallel, the equivalent resistance is calculated as follows:

$\displaystyle \frac{1}{R_e}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+...+\frac{1}{R_n}$

If we have 10 wires of resistance R/10 each and connect them in parallel, the equivalent resistance is:

$\displaystyle \frac{1}{R_e}=\frac{1}{R/10}+\frac{1}{R/10}+\frac{1}{R/10}...+\frac{1}{R/10}$

This sum is repeated 10 times. Operating each term:

$\displaystyle \frac{1}{R_e}=\frac{10}{R}+\frac{10}{R}+\frac{10}{R}+...+\frac{10}{R}$

All the terms have the same denominator, thus:

$\displaystyle \frac{1}{R_e}=10\frac{10}{R}=\frac{100}{R}$

Taking the reciprocals:

$R_e=R/100$

The equivalent resistance of the combination is R/100

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