A student woke up in the morning and checked the rain gauge in her backyard. The rain gauge was empty, but the grass was moist.
Which of the following best explains how this could happen?
A. It snowed, but did not rain during the night.
B. Run-off from a nearby river made the grass wet.
C. Water Vapor Condensed on the grass.
D. The water in the rain gauge evaporated, but the water on the grass did not.
Explain why you choose the answer you did.
THANK YOU!
A. It snowed, but did not rain during the night.
B. Run-off from a nearby river made the grass wet.
C. Water Vapor Condensed on the grass.
D. The water in the rain gauge evaporated, but the water on the grass did not.
Explain why you choose the answer you did.
THANK YOU!
2 answers:
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Answer:
1) 0.1584 m
2) To allow for expansion without derailment
3) 0.101376 m
4) 213.675 °C
5) 266.67 m
6) 8.33 × 10⁻⁶ /°C
7) The alloy meets the requirement
8) 1.95 × 10⁻³ /°C
9) 32.095 m
10) -12157.72°C
Explanation:
1) Equation for the coefficient of linear expansion =
Where:
ΔL = Change in length = Required
L = Initial length = 1.32 × 10⁴ m
= Coefficient of linear expansion of steel = 12 × 10⁻⁶ /°C
ΔT = Change in temperature = 37°C - 27°C = 10°C
Plugging the values in the equation for the temperature expansion of steel, we have m;
ΔL = L × ×ΔT = 1.32 × 10⁴ × 12 × 10⁻⁶ × 10 = 0.1584 m
2. Here we have that by segmenting railroad tracks into short pieces, the expansion of the metal tracks with temperature can be absorbed by the gaps between the segment without distorting the shape and direction (pattern) of the tracks
3. Here we have;
= Coefficient of linear expansion of iron = 12 × 10⁻⁶ /°C
ΔT = Temperature change = 27°C - 3°C = 24°C
L = Height of the Eiffel Tower = 352 meters
∴ ΔL = L × ×ΔT = 352 × 12 × 10⁻⁶ × 24 = 0.101376 m
Therefore, the height of the Eiffel Tower changes from 352 m to about 352.101376 m each year, with an average change in height experienced each year = 0.101376 m
4. Here, we have
L = 13.0 ft
ΔL = 1 in.
= 30 × 10⁻⁶ /°C
ΔT = Required temperature change
From
5. Here, we have;
∴ L = 1/(150×25 × 10⁻⁶) = 266.67 m
The bars original length = 266.67 m
6. Here we have;
Where:
ΔL = 3.00 - 3.002 = 0.002 m
L = 3.00 m
ΔT = 110°C - 30°C = 80°C
∴ = 0.002/(3.00 × 80) = 8.33 × 10⁻⁶ /°C
7. Here we have;
ΔL = L × ×ΔT = 3 × 8.33 × 10⁻⁶ × 210 = 0.00525 m
Therefore, final length = 3.00 m + 0.00525 m = 3.00525 m
Since 3.00525 m < 3.017 m hence the alloy meets the requirement.
8. Here, we have
L = 3.2 m
ΔL = 0.5 m
ΔT = 84°C - 24°C = 60°C
∴ = 0.5/(3.2 × 60) = 1.95 × 10⁻³ /°C
The coefficient of linear expansion of the material from which the rod is made = 1.95 × 10⁻³ /°C
9. Here, we have
Length of steel girder, L = 32.10 m
ΔT = 8°C - 22°C = -14°C
= 12 × 10⁻⁶ /°C
ΔL = L × ×ΔT
Hence ΔL = 32.1 × 12 × 10⁻⁶× -14 = -0.0054 m
New length = 32.1 - 0.0054 = 32.095 m
10. Here we have;
ΔL = 92.6 cm - 123 cm = -30.4 cm
= 2.0 × 10⁻⁵ /°C
L = 123 cm
∴
Therefore, the temperature will be 200 - 12357.724 = -12157.72°C.
Answer:
True
Explanation:
The tensile stress, σ, on a solid cylindrical wire is given by the following relationship;
Where;
= The tensile force
= The original cross sectional area of the cylindrical wire = π·R²
R = The radius of the wire
Therefore;
= σ ×
= σ × π × R²
Therefore, the tensile force is directly proportional to the square of the radius of the cylindrical wire, and as the radius of the wire increases, which is by increasing the thickness of the wire, the tensile force is largely increased
The correct option is; True.