Based on the data provided, there are 25 g of calcium carbonate in 1.505 × 10^23 atoms.
<h3>What is the moles of calcium carbonate in 1.505 × 10^23 atoms of calcium carbonate?</h3>
The mole of a substance can be calculated as follows:
- Moles of substance = number of particles/6.02 × 10^23
Moles of calcium carbonate = 1.505 × 10^23/6.02 × 10^23
Moles of calcium carbonate = 0.25 moles
The mass of calcium carbonate in 0.25 moles is calculated as follows:
- mass = moles × molar mass
molar mass of a calcium carbonate = 100 g/mol
mass of calcium carbonate = 0.25 × 100 = 25 g.
Therefore, there are 25 g of calcium carbonate in 1.505 × 10^23 atoms.
Learn more about molar mass and mass at: brainly.com/question/15476873
Answer:
a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change
<em>Que quieres clasificar?.... Yo te puedo ayudar si quieres pero dime que quieres clasificar.</em>
Answer
a) Group 16
b) Group 1
c) Group 15
d)
e)
f) Sodium
g) Oxygen
h) Phosphorus
Procedure
Using the periodic table below identify the elements. The periodic table organizes elements in a way that reflects their number and pattern of electrons. The table places elements into columns—groups—and rows—periods.
An element’s column number gives information about its number of valence electrons and reactivity. In general, the number of valence electrons is the same within a column and increases from left to right within a row. Applies only for groups 1,2, 13-18 (remembering that from 13 to 18 the last number is the valence).
