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Yuki888 [10]
4 years ago
8

Find the equation of a line which passes through the point (3, -1) with the gradient M=2÷3​

Mathematics
1 answer:
cluponka [151]4 years ago
7 0

Step-by-step explanation:

Equ of line -

y=mx+c

Using point (3,-1)

3 as x, - 1 as y

M=2/3

Substitute the values of these coordinates

3=2/3(-1) +c - - - - now find for c

c= 3- (-2/3)

c= 3.67

Now with the value of c, put the values back into the equation form .. Assuming we don't have a point to work with

y=2/3x + 3.67

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