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Yuki888 [10]
3 years ago
8

Find the equation of a line which passes through the point (3, -1) with the gradient M=2÷3​

Mathematics
1 answer:
cluponka [151]3 years ago
7 0

Step-by-step explanation:

Equ of line -

y=mx+c

Using point (3,-1)

3 as x, - 1 as y

M=2/3

Substitute the values of these coordinates

3=2/3(-1) +c - - - - now find for c

c= 3- (-2/3)

c= 3.67

Now with the value of c, put the values back into the equation form .. Assuming we don't have a point to work with

y=2/3x + 3.67

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If your dog eats 7/8 lb of food in 4 meals,how many meals will take your dog to eat 1 lb of food
Naddik [55]
I would say 5 meals. 7/8 =.875. .875/4=.218. .218+.875=1.09 so the dog would eat 1.09 lb ofdog foodafter 5 meals
8 0
3 years ago
Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p
kvv77 [185]

The question is an illustration of composite functions.

  • Functions c(n) and h(n) are \mathbf{c(n) = 5000 + 250n} and \mathbf{n(h) = 5h}
  • The composite function c(n(h)) is \mathbf{c(n(h)) = 5000 + 1250h}
  • The value of c(n(100)) is \mathbf{c(n(100)) = 130000}
  • The interpretation is: <em>"the cost of working for 100 hours is $130000"</em>

The given parameters are:

  • $5000 in fixed costs plus an additional $250
  • 5 systems in one hour of production

<u>(a) Functions c(n) and n(h)</u>

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

\mathbf{c(n) = Fixed + Additional \times n}

This gives

\mathbf{c(n) = 5000 + 250 \times n}

\mathbf{c(n) = 5000 + 250n}

The function for number of systems is:

\mathbf{n(h) = 5 \times h}

\mathbf{n(h) = 5h}

<u>(b) Function c(n(h))</u>

In (a), we have:

\mathbf{c(n) = 5000 + 250n}

\mathbf{n(h) = 5h}

Substitute n(h) for n in \mathbf{c(n) = 5000 + 250n}

\mathbf{c(n(h)) = 5000 + 250n(h)}

Substitute \mathbf{n(h) = 5h}

\mathbf{c(n(h)) = 5000 + 250 \times 5h}

\mathbf{c(n(h)) = 5000 + 1250h}

<u>(c) Find c(n(100))</u>

c(n(100)) means that h = 100.

So, we have:

\mathbf{c(n(100)) = 5000 + 1250 \times 100}

\mathbf{c(n(100)) = 5000 + 125000}

\mathbf{c(n(100)) = 130000}

<u>(d) Interpret (c)</u>

In (c), we have: \mathbf{c(n(100)) = 130000}

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110

5 0
3 years ago
Lorenzo buys 3 shirts at S dollars a piece and 2 pairs of pants at P dollars a pair. What does the expression 3s + 2p represent?
ryzh [129]

Answer:

The expression 3s + 2p represent total price of 3 shirts and 2 pairs of pants.

Step-by-step explanation:

It is given that

Price of a shirt = S dollar

Price of a pair of pants = P

Total number of shirts = 3

Total number of pairs of pants = 2

Total price = Quantity × Price of each unit

Total price of 3 shirts = 3S

Total price of 2 pairs of pants = 2P

Total price of 3 shirts and 2 pairs of pants = 3S + 2P

Therefore the expression 3s + 2p represent total price of 3 shirts and 2 pairs of pants.

3 0
3 years ago
Read 2 more answers
A chord 12cm long subtends an angle of 40° at the centre of the circle. calculate the radius of the circle.
kramer
Ok 12cm 40• is 50 minutes
5 0
2 years ago
Joe jumped 60 inches. Omar jumped 4 feet, 10 inches. Who jumped farther? <br> Explain your thinking.
Alecsey [184]

Answer:

Joe jumped farther because 60in is greater than 58in

Step-by-step explanation:

First you need to convert 4ft 10in into just inches in order to compare distances:

there are 12in per foot so 4(12)= 48 add the 10 in =58in

Joe jumped 60in and Omar jumper 58in

3 0
3 years ago
Read 2 more answers
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