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KatRina [158]
3 years ago
5

A plane flying horizontally at an altitude of 1 mi and a speed of 580 mi/h passes directly over a radar station. Find the rate a

t which the distance from the plane to the station is increasing when it is 2 mi away from the station. Round your answer to the nearest whole number.
Physics
1 answer:
shusha [124]3 years ago
8 0
<span> the tangent function of 2mi/5mi = 21.8 degrees
cosine of that angle = cos (21.8 degrees)
                                =0.928
 multiply 0.928 with 570 = 570*0.928
     Closing velocity         =  529.23 mph
</span><span>As the plane gets closer to radar station, tangent function becomes infinity and the cosine function becomes zero.....
</span>0*570 = 0 
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In this problem, we have

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r = 1.0 m (distance from the charge)

Solving the equation for q, we find the charge:

q=\frac{Er^2}{k}=\frac{(1.0 N/c)(1.0 m)^2}{9\cdot 10^9 Nm^2c^{-2}}=1.1\cdot 10^{-10}C

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Energy is inversely proportional to the wavelength of a wave. Which would have the GREATEST energy? A wave with a
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A 5

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       E  = h f  = \frac{hc}{wavelength}

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2 years ago
An automobile tire having a temperature of
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Answer:

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Explanation:

To solve this problem we will use the ideal gas equation, recall that the ideal gas state equation is always worked with absolute values.

P * v = R * T

where:

P = pressure [Pa]

v = specific volume [m^3/kg]

R = gas constant for air = 0.287 [kJ/kg*K]

T = temperature [K]

<u>For the initial state</u>

<u />

P1 = 24 [Psi] + 14.7 = 165.47[kPa] + 101.325 = 266.8 [kPa] (absolute pressure)

T1 = -2.6 [°C] = - 2.6 + 273 = 270.4 [K] (absolute Temperature)

Therefore we can calculate the specific volume:

v1 = R*T1 / P1

v1 = (0.287 * 270.4) / 266.8

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And converting this value to Psig

Psm = 30.66 [Psig]

3 0
3 years ago
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