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11 months ago

Except for the nodes on a standing wave, what is the frequency f of the points executing simple harmonic motion?

1 answer:

6 0

Take into account that in a standing wave, the frequency f of the points executing simple harmonic motion, is simply a multiple of the fundamental harmonic fo, that is:

f = n·fo

where n is an integer and fo is the first harmonic or fundamental.

fo is given by the length L of a string, in the following way:

fo = v/λ = v/(L/2) = 2v/L

becasue in the fundamental harmonic, the length of th string coincides with one hal of the wavelength of the wave.

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A mass is attached to a vertical spring, which then goes into oscillation. At the high point of the oscillation, the spring is i

andrew-mc [135]

Answer:

0.34 sec

Explanation:

Low point of spring ( length of stretched spring ) = 5.8 cm

midpoint of spring = 5.8 / 2 = 2.9 cm

Determine the oscillation period

at equilibrum condition

Kx = Mg

g= 9.8 m/s^2

x = 2.9 * 10^-2 m

k / m = 9.8 / ( 2.9 * 10^-2 ) = 337.93

note : w = $\sqrt{k/m}$ = $\sqrt{337.93}$ = 18.38 rad/sec

Period of oscillation = $2\pi / w$

= 0.34 sec

8 0

2 years ago

Your backpack has a mass of 8 kg. You drop it from a height of 1.3m. How much work is done by gravity as the backpack falls?

olga_2 [115]

Answer:

The answer is C.

Explanation:

I guessed and it was right

6 0

2 years ago

Read 2 more answers

A jet plane comes in for a downward dive as shown in the figure below.

xxTIMURxx [149]

The solution would be like this for this specific problem:

5.5 g = g + v^2/r 
4.5 g = v^2/r 
v^2 = 4.5 g * r 
v = sqrt ( 4.5 *9.81m/s^2 * 350 m) 
v = 124 m/s

So the pilot will black out for this dive at 124 m/s. I am hoping that these answers have satisfied your query and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

8 0

3 years ago

Read 2 more answers

A resistor R and another resistor 2R are connected in a series across a battery. If heat is produced at a rate of 10W in R, then

alekssr [168]

Answer:

Option B

Solution:

As per the question:

Heat produced at the rate of 10 W

The resistor R and 2R are in series.

Also, in series, same current, I' passes through each element in the circuit.

Therefore, current is constant in series.

Also,

Power, $P' = I'^{2}R$

When current, I' is constant, then

P' ∝ R

Thus

$\frac{P'}{2R} = \frac{10}{R}$

P' = 20 W

5 0

2 years ago

as an aid in understanding this problem. The drawing shows a positively charged particle entering a 0.61-T magnetic field. The p

miv72 [106K]

Answer:

E = 420.9 N/C

Explanation:

According to the given condition:

$Net\ Force = 2(Magnetic\ Force)\\Electric\ Force - Magnetic\ Force = 2(Magnetic\ Force)\\Electric\ Force = 3(Magnetic\ Force)\\qE = 3qvBSin\theta\\E = 3vBSin\theta$

where,

E = Magnitude of Electric Field = ?

v = speed of charge = 230 m/s

B = Magnitude of Magnetic Field = 0.61 T

θ = Angle between speed and magnetic field = 90°

Therefore,

$E = (3)(230\ m/s)(0.61\ T)Sin90^o$

E = 420.9 N/C

3 0

2 years ago