You can find
1) time to hit the ground
2) initial velocity
3) speed when it hits the ground
Equations
Vx = Vxo
x = Vx * t
Vy = Vyo + gt
Vyo = 0
Vy = gt
y = yo - Vyo - gt^2 / 2
=> yo - y = gt^2 / 2
1) time to hit the ground
=> 8.0 = g t^2 / 2 => t^2 = 8.0m * 2 / 9.81 m/s^2 = 1.631 s^2
=> t = √1.631 s^2 = 1.28 s
2) initial velocity
Vxo = x / t = 6.5m / 1.28s = 5.08 m/s
3) speed when it hits the ground
Vy = g*t = 9.81 m/s * 1.28s = 12.56 m/s
V^2 = Vy^2 + Vx^2 = (12.56 m/s)^2 + (5.08 m/s)^2 = 183.56 m^2 / s^2
=> V = √ (183.56 m^2 / s^2) = 13.55 m/s
That's unaccelerated motion,
and constant velocity.
Answer:
The weight is the same
3
lb
explanation
See explanation.
Explanation:
If by weight you mean the physical value measured in
l
b (or k
g
) usually called mass, then this value does not depend on a place where object is located. Object's mass would be the same everywhere even if you put it on Mars or the Sun.
The value which changes is the gravitational force. In your example it is
10
2
=
100 times greater on the Earth's surface than in the point 10 Earth's radii from its center.
Answer:
Explanation:
Energy is transferred from the sun to Earth via electromagnetic waves, or radiation. Most of the energy that passes through the upper atmosphere and reaches Earth's surface is in two forms, visible and infrared light. ... Once energy has been absorbed by the Earth system, it is transformed and transferred
