Answer:
- second kick goes farther
- first kick goes higher
Step-by-step explanation:
Assuming the kick started from ground level, the path of the ball is assumed to be symmetrical about the high point. That is, the first kick will land 2×20 = 40 yards downfield.
The equation for the second kick can be rewritten as ...
y = 0.008x(50 -x)
The value of y will be zero at x=0 and at x=50. The second kick will land 50 yards downfield, a greater distance than the first kick.
At x=25, the height of the second kick is ...
y = 0.008(25)(50-25) = 5 . . . yards
The second kick travels farther (50 yds vs. 40 yds).
The first kick travels higher (8 yds vs. 5 yds).
Answer:
A man is viewing the plane from a position. 3000 ft from the base of a radio tower. The airplane is flying horizontally away from the man. If the plane is flying at the rate of 600 ft/sec, at what rate is the distance between ...
Line up the equations and add them up, adding the x's together then y's (which should cancel out) then the totals.
Then the equation should equal -9x=36 and when tou solve x= -4.
Plug -4 in for x in one of the equations, I chose the second one, and solve.
y = -21
Hope this helps! :)