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Zepler [3.9K]
3 years ago
13

How many grams of sodium acetate are in solution in the third beaker?

Chemistry
1 answer:
Kipish [7]3 years ago
6 0

Answer:

46g of sodium acetate.

Explanation:

The data is: <em>Precipitation from a supersaturated sodium acetate solution. The solution on the left was formed by dissolving 156g of the salt in 100 mL of water at 100°C and then slowly cooling it to 20°C. Because the solubility of sodium acetate in water at 20°C is 46g per 100mL of water, the solution is supersaturated. Addition of a sodium acetate crystal causes the excess solute to crystallize from solution.</em>

The third solution is the result of the equilibrium in the solution at 20°C. As the maximum quantity that water can dissolve of sodium acetate at this temperature is 46g per 100mL and the solution has 100mL <em>there are 46g of sodium acetate in solution. </em>The other sodium acetate precipitate because of decreasing of temperature.

I hope it helps!

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                                  B +   H₂O    ⇄     BH⁺ +        OH⁻

At t=0                        0.4                          -              -

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Solving for x, we get:

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pOH = -log[OH⁻] = -log(2.4606×10⁻³) = 2.61

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