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2 years ago

Contact metamorphism occurs over a localized area when magma moves into the crust. true or false

Physics

1 answer:

GenaCL600 [577]2 years ago

3 0

Answer:

TRUE

Explanation:

When the hot and less dense magma rises up towards the surface, the country rocks are heated due to the increasing temperature of the magma. This results in the formation of an aureole that surrounds the intruded magma body. This aureole is commonly known as the metamorphic aureole and contact metamorphism occurs in this area. This type of process occurs at a comparatively smaller area, and where there is a high temperature and low-pressure condition. For example, Hornfels and Marble.

Thus, the above-given statement is True.

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A2 kg block is accelerating at the rate of 5 m/s² while being acted on by two forces. One of the forces equals 30 N, 0°. What ar

Mademuasel [1]

Answer:

20 [N], in the opposite direction of the first force.

Explanation:

We know that newton's second law stipulates that the sum of forces on a body must be equal to the product of mass by acceleration.

$SumF = m*a\\30 + F = 2*5\\F = 30 - (2*5)\\F = - 20 [N]$

The negative sign means that the other force acting on the body must be in the opposite direction to the force of 30 [N]

6 0

2 years ago

Which scientist saw the atom as a positively charged sphere with negative particles ( electrons ) embedded within?

Zigmanuir [339]

Ernest Rutherford is the answer you are looking for my friend.

5 0

3 years ago

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A 10,000kg space ship is orbiting the moon with a radius of 25km from the ship to the center of the moon. It's tangential speed

galina1969 [7]

Answer:

False

Explanation:

ac = v^2/r

acceleration is not dependent on the mass of the orbiting object.

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2 years ago

Baseball player A bunts the ball by hitting it in such a way that it acquires an initial velocity of 1.3 m/s parallel to the gro

pashok25 [27]

Answer:

Explanation:

cSep 20, 2010

well, since player b is obviously inadequate at athletics, it shows that player b is a woman, and because of this, she would not be able to hit the ball. The magnitude of the initial velocity would therefore be zero.

Anonymous

Sep 20, 2010

First you need to solve for time by using

d=(1/2)(a)(t^2)+(vi)t

1m=(1/2)(9.8)t^2 vertical initial velocity is 0m/s

t=.45 sec

Then you find the horizontal distance traveled by using

v=d/t

1.3m/s=d/.54sec

d=.585m

Then you need to find the time of player B by using

d=(1/2)(a)(t^2)+(vi)t

1.8m=(1/2)(9.8)(t^2) vertical initial velocity is 0

t=.61 sec

Finally to find player Bs initial horizontal velocity you use the horizontal equation

v=d/t

v=.585m/.61 sec

so v=.959m/s

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3 years ago

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You need to put a metal rod

Lubov Fominskaja [6]

-- Put the rod into the freezer for a while. As it cools,
it contracts (gets smaller) slightly.

-- Put the cylinder into hot hot water for a while. As it heats,
it expands (gets bigger) slightly.

-- Bring the rod and the cylinder togther quickly, before the
rod has a chance to warm up or the cylinder has a chance
to cool off.

-- I bet it'll fit now.

-- But be careful . . . get the rod exactly where you want it as fast
as you can. Once both pieces come back to the same temperature,
and the rod expands a little and the cylinder contracts a little, the fit
will be so tight that you'll probably never get them apart again, or even
move the rod.

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2 years ago