The force applied by the competitor is littler than the heaviness of the barbell. At the point when the barbell quickens upward, the power applied by the competitor is more prominent than the heaviness of the barbell. When it decelerates upward, the power applied by the competitor is littler than the heaviness of the barbell.
Here when car in front of us applied brakes then it is slowing down due to frictional force on it
So here we can say that friction force on the car front of our car is given as

So the acceleration of car due to friction is given as



now it is given that


so here we have


so the car will accelerate due to brakes by a = - 8.52 m/s^2
Answer
Time period T = 1.50 s
time t = 40 s
r = 6.2 m
a)
Angular speed ω = 2π/T
=
= 4.189 rad/s
Angular acceleration α = 
= 
= 0.105 rad/s²
Tangential acceleration a = r α = 6.2 x 0.105 = 0.651 m/s²
b)The maximum speed.
v = 2πr/T
= 
= 25.97 m/s
So centripetal acceleration.
a = 
= 
= 108.781 m/s^2
= 11.1 g
in combination with the gravitation acceleration.


Answer:
Following are the solution to the given question:
Explanation:
Its strength from both charges is equivalent or identical. The power is equal. And it is passed down

Therefore, the extent doesn't rely on the fact that charges are the same or different. Newton's third law complies with Electrostatic Charges due to a couple of charges. They are similar in magnitude, and they're in the other way.

question: Please help!!!
If a bottle is being squeezed with a force of 10 Newtons and the area of the bottle is 15
squared inches. What is the pressure??
Answer:
1025.64 N/m²
Explanation:
Pressure: This can be defined as the ratio of force to area. The si unit of pressure is N/m².
From the question,
P = F/A........................ Equation 1
Where F = Force, A = Area.
Given: F = 10 Newtons, A = 15 Squared Inches = (15×0.00065) = 0.00975 m²
Substitute these values into equation 1
P = 10/0.00975
P = 1025.64 N/m²
Hence the pressure of the bottle is 1025.64 N/m²