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Genrish500 [490]
3 years ago
9

The circuit has a 3 volt EMF and two ohm resistors. How much power in watts does this circuit draw? A) 4.5 , B) 24, C) 1.13 D) 2

.67 E) 0.375 F) 1.5
Physics
1 answer:
dlinn [17]3 years ago
5 0

Answer:

P = 4.5 watts

Explanation:

Given that,

EMF of the circuit, E = 3 volt

The resistance  of the resistors, R = 2 ohms

We need to find the power of this circuit. The relation between power, emf and resistance is given by the formula as follows :

P=\dfrac{V^2}{R}

Substitute all the values,

P=\dfrac{3^2}{2}\\\\P=4.5\ W

So, the power of this circuit is equal to 4.5 watts.

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A car moves in a circular motion and it is subject to a centripetal acceleration of 24 m/s2. If the radius of the circular path
Softa [21]

Answer:

Explanation:

Centripetal acceleration is given by:

a_{c} = v^{2}/r

Thus, centripetal acceleration is inversely proportional to the radius. Thus, when radius will double, the centripetal acceleration will be halved.

3 0
4 years ago
If an X-ray tube is operating at a current of 30.0 mA:a) How many electrons are striking the target per second? b) If the potent
Zina [86]

Answer:

Explanation:

A. Q= It

30E-3A=q

Ne = q

30E-3/1.6*10-19= N

N= 1.8*10^16 electrons

B. Power= I x v

= 30*10^-3A x 100*10^3v

= 3000watts

3 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
matrenka [14]

the answer is d it reflects all the wavelengths of visible light.

4 0
4 years ago
Read 2 more answers
A 290 gg bird flying along at 6.2 m/sm/s sees a 9.0 gg insect heading straight toward it with a speed of 34 m/sm/s (as measured
Murrr4er [49]

Answer:

The bird's speed immediately after swallowing is 4.98 m/s.

Explanation:

Given that,

Mass of bird = 290 g

Speed = 6.2 m/s

Mass of sees = 9.0 g

Speed = 34 m/s

We need to calculate the bird's speed immediately after swallowing

Using conservation of momentum

m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})v_{3}

Put the value into the formula

0.290\times6.2+0.009\times(-34)=(0.290+0.009)\times v_{3}

v_{3}=\dfrac{0.290\times6.2-0.009\times34}{(0.290+0.009)}

v_{3}=4.98\ m/s

Hence, The bird's speed immediately after swallowing is 4.98 m/s.

6 0
3 years ago
How would the period of a simple pendulum be affected if it were located on the moon instead of the earth?
OlgaM077 [116]

Answer:

On moon time period will become 2.45 times of the time period on earth

Explanation:

Time period of simple pendulum is equal to T=2\pi \sqrt{\frac{l}{g}} ....eqn 1 here l is length of the pendulum and g is acceleration due to gravity on earth

As when we go to moon, acceleration due to gravity on moon is \frac{1}{6} times os acceleration due to gravity on earth

So time period of pendulum on moon is equal to

T_{moon}=2\pi \sqrt{\frac{l}{\frac{g}{6}}}=2\pi \sqrt{\frac{6l}{g}} --------eqn 2

Dividing eqn 2 by eqn 1

\frac{T_{moon}}{T}=\sqrt{\frac{6l}{g}\times \frac{g}{l}}

T_{moon}=\sqrt{6}T=2.45T

So on moon time period will become 2.45 times of the time period on earth

5 0
3 years ago
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