Answer:
metal atom
Explanation:
metallic solid has layers makes it soft and it also has electron that can carry charge and conduct electricity.
Answer:
Mole fraction H₂ = 0.29
Partial pressure of H₂ → 88.5 kPa
Explanation:
You need to know this relation to solve this:
Moles of a gas / Total moles = Partial pressure of the gas / Total pressure
Total moles = 3 mol + 7.3 mol → 10.3 moles
Mole fraction H₂ → 3 moles / 10.3 moles = 0.29
Mole fraction = Partial pressure of the gas / Total pressure
0.29 . 304 kPa = Partial pressure of H₂ → 88.5 kPa
Considering the ideal gas law, there are 279.42 moles of acetylene in the tank.
<h3>Definition of ideal gas</h3>
Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.
<h3>Ideal gas law</h3>
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:
P×V = n×R×T
<h3>Moles of acetylene</h3>
In this case, you know:
- P= 1765 kPa= 17.4192 atm (being 101.325 kPa= 1 atm)
- V= 390 L
- n= ?
- R= 0.082

- T= 23.5 °C= 296.5 K (being 0 °C= 273 K)
Replacing in the ideal gas law:
17.4192 atm× 390 L = n×0.082
× 296.5 K
Solving:

<u><em>n= 279.42 moles</em></u>
Finally, there are 279.42 moles of acetylene in the tank.
Learn more about ideal gas law:
brainly.com/question/4147359
<u>Answer:</u> For the given reaction, the value of
is greater than 1
<u>Explanation:</u>
For the given chemical equation:
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The expression of
for above equation follows:
![K_c=\frac{[Ca^{2+}]\times [CO_3^{2-}]}{[CaCO_3}]\\\\K_c=[Ca^{2+}]\times [CO_3^{2-}]](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCa%5E%7B2%2B%7D%5D%5Ctimes%20%5BCO_3%5E%7B2-%7D%5D%7D%7B%5BCaCO_3%7D%5D%5C%5C%5C%5CK_c%3D%5BCa%5E%7B2%2B%7D%5D%5Ctimes%20%5BCO_3%5E%7B2-%7D%5D)
The concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression
As, the denominator is missing and the numerator is the only part left in the expression. So, the value of
will be greater than 1.
Hence, for the given reaction, the value of
is greater than 1