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ladessa [460]
3 years ago
13

OK SO HERES HOW ITS GONNA GO. IMA ASK YOU GUYS ONE MORE TIME BC THIS IS LIKE THE 3RD TIME IVE WAISTED MY POINTS IN THE SAME QUES

TION. IGHT JUST TRY.
MY TEACHER PIS.S.ES ME OFF I NEED HELP I SWEAR.

Question:
Give the electron configuration for the calcium ion. (2points)

My Answer:
(AR)4s^2

0/2 points

Teachers response:
This is asking for the ion and that is the neutral configuration. Write out the whole thing.
^
|
|
Help on that plz
Chemistry
1 answer:
Ne4ueva [31]3 years ago
4 0

Answer:

Electronic Configuration of calcium ion: Ca²⁺

1s², 2s², 2p⁶, 3s², 3p⁶

Explanation:

Calcium belong to group IIA and known as alkaline earth metals.

  • it have two electrons in outer most orbital.
  • these outer two electrons are involve in bonding
  • calcium lose these two electron and form cation
  • cation have 2+ charge
  • calcium have total twenty electrons

Electronic Configuration of calcium atom: ²⁰Ca

1s², 2s², 2p⁶, 3s², 3p⁶, 4s²

When calcium ion is form it loses two electron and have 2+ charge on it.

and have total of 18 electrons

So,

Electronic Configuration of calcium ion: Ca²⁺

the last filled orbital will be 3p⁶

1s², 2s², 2p⁶, 3s², 3p⁶

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Calculate the molarity of a solution of potassium hydroxide if 19.55 mL of KOH is required for the titration of a 20.20 mL sampl
VMariaS [17]

Answer:

The correct answer is 0.3582 M.

Explanation:

Based on the given information, the volume of KOH given is 19.55 ml, the volume of sulfuric acid given is 20.20 ml, and the molarity of sulfuric acid is 0.3467 M. There is a need to find the molarity of KOH.

The formula to use in the given case is,

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Here M1 is the molarity of KOH, V1 is the volume of KOH, M2 is the molarity of sulfuric acid, and V2 is the volume of H2SO4.

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