Cl2(g) -------> Cl-(aq) + ClO-(aq)
2e- + Cl2(g) -------> 2Cl-(aq) [reduction]
4OH-(aq) + Cl2(g) -----------> 2ClO-(aq) + 2H2O(l) + 2e- [oxidation]
______________________________________...
2OH-(aq) + Cl2(g) --------> Cl-(aq) + ClO-(aq) + H2O(l)
Answer is: electron in 2pz orbital.
The principal quantum number is one
of four quantum numbers which are assigned to each electron in
an atom to describe that electron's state, n=1,2,3... n=2 - <span>the </span>second energy level.<span>
The azimuthal quantum number is a quantum number for
an atomic orbital that determines its orbital angular
momentum and describes the shape of the orbital. l = 0,1...n-1, when l = 1, that is p </span>subshell.
The magnetic quantum number<span>, </span><span>ml, show</span> orbital<span> in which the electron is located, ml = -l...+l, ml = 0 is pz orbital.</span>
The spin quantum number<span>, </span><span>ms</span><span>, is the spin of the electron; ms = +1/2 or -1/2.</span>
Answer:
See the explanation
Explanation:
In this case, in order to get an <u>elimination reaction</u> we need to have a <u>strong base</u>. In this case, the base is the phenoxide ion produced the phenol (see figure 1).
Due to the resonance, we will have a more stable anion therefore we will have a less strong base because the negative charge is moving around the molecule (see figure 2).
Finally, the phenoxide will attack the <u>primary carbon</u> attached to the Cl. The C-Cl bond would be broken and the C-O would be produced <u>at the same time</u> to get a substitution (see figure 1).
なたはたさたやたはたはたはたはやはたはたなたな田畑な田畑の
