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kirza4 [7]
4 years ago
10

Show a numerical setup for calculating the quantity of heat in joules required to completely vaporize 102.3 grams of H2O(l) at 1

00°C and 1.0 atm.
Chemistry
1 answer:
s2008m [1.1K]4 years ago
5 0

Answer:

The heat required to vaporize 102.3 grams of H₂O(l) is 231198 J.

Explanation:

The heat required to vaporize 102.3 g of H₂O(l) can be calculated as follows:

q = m*\Delta H_{v}

Where:

q: is the heat  

ΔHv: is the heat of vaporization of water = 2260 J/g

m: is the mass = 102.3

q = m*\Delta H_{v} = 102.3 g*2260 J/g = 231198 J

Therefore, the heat required to vaporize 102.3 grams of H₂O(l) is 231198 J.

I hope it helps you!

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