<span>ΔE = -RH [(1/nf2) - (1/ni2)]ΔE = -2.18 x10-18 J [(1/32) - (1/52)]ΔE = -1.55 x10-19 JE = hc/λλ = hc/Eλ = [(6.63 x10-34 J.s.) x (3.00 x1017 nm/s)] /(1.55 x10-19 J)λ = 1280nm</span>
What are the answer choices?
Candela is the correct answer. In measuring the brightness or luminosity of the bulb and you want to use the metric system, candela is the unit to be used. You are correct that candela is the unit of light intensity. The term candela is the Latin for candle which signifies light.<span> </span>
Answer:
34.9103 or 34.9 g
Explanation:
Remember Density is a broken heart: m/v.
In this scenario (Let x = # of grams in the sample of gasoline),
D = 0.7198 g/mL = x g / 48.5 mL
So,
(0.7198 g/mL) * (48.5 mL) = x g
x g = 34.9103 = 34.9 g (Accounting for Significant Figures)
Answer:
Results
The percent error between 20 and 20.5 is 2.5%
Explanation:
Percent Error = | (20.5 − 20) / 20 | × 100 = | (0.5) / 20 | × 100 = | 0.025 | × 100 = 2.5% (three decimal places)Percent Error = 2.5%
