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frozen [14]
3 years ago
13

(SAT Prep) In the figure, what is the length of BC?

Mathematics
2 answers:
nataly862011 [7]3 years ago
8 0
The answer is 18 I took the test
TiliK225 [7]3 years ago
6 0

Answer:

I got 18 as my answer

Step-by-step explanation:

I made a triangle with the right side by dropping a vertical. Lets call the point straight down from C, E

Then I found the angle of D

sin θ = 5/13

θ = sin-¹(5/13)

θ≅22.619°

Then I found length of DE by

cosθ (remember we know what theta is) = X/13

12cosθ = X

X = 12

The length of DE is 12.

Since AD is 30, and the left side has two right angles we can do

AD - DE to find BC.

30-12 is 18

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What is the remainder when 19x^2 + 15x + 12 is divided by x - 2?
Aleksandr-060686 [28]

Answer:

R = 118

Step-by-step explanation:

Given

Represent the polynomial with P and the divisor with D

P = 19x^2 + 15x + 12

D = x -2

Required

Determine the remainder

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i.e.

D = 0

x - 2 = 0

x = 2

Substitute 2 for x in the polynomial.

This gives remainder (R)

R = 19*2^2 + 15*2 + 12

R = 19*4 + 15*2 + 12

R = 76 + 30 + 12

R = 118

<em>Hence, the remainder is 118</em>

8 0
3 years ago
Can someone solve this question?
Rom4ik [11]

The triangles are isosceles. The following notation are for the angles. For example ABD is refer to the angle located in the B vertex, formed by the segments AB and BD.

ABD = ADB\\40 + 2ADB = 180\\ADB = 70 = ABD\\

70 +  DBC + 30 = 180\\DBC = 180 - 100 = 80

Then

BCD = BCD\\2BCD + 80 = 180\\BCD = 50



3 0
3 years ago
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