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3 years ago

What is the correct evaluation of 4x2 - 2x + 5, when x is equal to 2?

Mathematics

1 answer:

meriva3 years ago

3 0

Answer:

Step-by-step explanation:

Rewrite the problem

4x2-2(2)+5

2. Solve the problem. Do the multiplication first and then the subtraction and addition

8-2(2)+5

8-4+5

4+5

The final answer is 9

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594 is 450% of what number?

r-ruslan [8.4K]

Answer: 2,673

Step-by-step explanation:

450% × 594 =

(450 ÷ 100) × 594 =

(450 × 594) ÷ 100 =

267,300 ÷ 100 =

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4 years ago

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Jordan is a student who hates to be called on in class. His teacher randomly calls on students and Jordan knows that on any give

Anika [276]

Answer:

0.1 for each case

Step-by-step explanation:

Because Jordan's teacher randomly calls on students and Jordan has 10% chance of being called on any given day, the probability that on the first day Jordan is called on is 0.1 Besides, the probability remains constant on any given day, so, the probability that on the 2nd day Jordan is called on is 0.1 and for the 5th day is the same 0.1 Probability is always a number between 0 and 1.

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3 years ago

Help please!!!!!!!!!!!!

creativ13 [48]

Answer:

$\frac{\pi }{3},\:\frac{2\pi }{3}$

Step-by-step explanation:

Let a=THETA (angle)

$1+\sin \left(a\right)-1=\frac{\sqrt{3}+2}{2}-1\\\sin \left(a\right)=\frac{\sqrt{3}+2}{2}-1\\a=\arcsin \left(\frac{\sqrt{3}+2}{2}-1\right)+2\pi n,\:a=\pi -\arcsin \left(\frac{\sqrt{3}+2}{2}-1\right)+2\pi n\\a=\frac{\pi }{3},\:a=\frac{2\pi }{3}$

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3 years ago

in a five character password the first two characters must be digits and the last three characters must be letters if no charact

Vilka [71]

Answer:

1,404,000 unique passwords are possible.

Step-by-step explanation:

The order in which the letters and the digits are is important(AB is a different password than BA), which means that the permutations formula is used to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

In this question:

2 digits from a set of 10(there are 10 possible digits, 0-9).

3 characters from a set of 26. So

$P_{10,2}P_{26,3} = \frac{10!}{8!} \times \frac{26!}{23!} = 10*9*26*25*24 = 1404000$

1,404,000 unique passwords are possible.

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3 years ago

26. A football team ran four plays. The

-Dominant- [34]

Answer:

-10 would be your answer.

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3 years ago