The new square has length: 10 + l, where l is the original length of the square, and it's area is (10 + l)^2;
So, we solve the equation: 3 x l^2 = (10 + l)^2;
Then, 3 x l^2 = 100 + 20 x l + l^2;
Finally, 2xl^2 - 20xl - 100 = 0; / ÷2;
l^2 - 10l - 50 = 0 (we use the quadratic equation formula);
The only positive solution is l = 5(1+ \sqrt{3} );
I think you got confused with the 50 and 90.
Read my NOTE there it will surely help you answering other questions like this
Answer:
vertex (0.875, 0.9375) AoS x=0.875
Step-by-step explanation:
let 2x+5y=12......... equation I
also,4x+3y=-4........ equation ii
now, multiply equation i by 2
we get,2(2x+5y=12)
or,4x+10y=24
now subtract i from ii
4x+10y=24
-4x+3y=-4
so,the answer be 7y=28
or,y=4
now putting the value of y in equation I we get,
4x+10y=24
or,4x+10.4=24
or, 4x=24-40
or, 4x=16
or,x=4
therefore, the value of x and y are 4and 4
