The missing digit is number 3. The total amount should be $132
I multiplied 11 by the numbers 10 and above to get the possible three digit answer who has 1 as the first digit and 2 as the last digit.
11 x 10 = 110
11 x 11 = 121
11 x 12 = 132
The 11 members of the Middle School Math club each paid $12 for a guest speaker.
I suppose you just have to simplify this expression.
(2ˣ⁺² - 2ˣ⁺³) / (2ˣ⁺¹ - 2ˣ⁺²)
Divide through every term by the lowest power of 2, which would be <em>x</em> + 1 :
… = (2ˣ⁺²/2ˣ⁺¹ - 2ˣ⁺³/2ˣ⁺¹) / (2ˣ⁺¹/2ˣ⁺¹ - 2ˣ⁺²/2ˣ⁺¹)
Recall that <em>n</em>ª / <em>n</em>ᵇ = <em>n</em>ª⁻ᵇ, so that we have
… = (2⁽ˣ⁺²⁾ ⁻ ⁽ˣ⁺¹⁾ - 2⁽ˣ⁺³⁾ ⁻ ⁽ˣ⁺¹⁾) / (2⁽ˣ⁺¹⁾ ⁻ ⁽ˣ⁺¹⁾ - 2⁽ˣ⁺²⁾ ⁻ ⁽ˣ⁺¹⁾)
… = (2¹ - 2²) / (2⁰ - 2¹)
… = (2 - 4) / (1 - 2)
… = (-2) / (-1)
… = 2
Another way to get the same result: rewrite every term as a multiple of <em>y</em> = 2ˣ :
… = (2²×2ˣ - 2³×2ˣ) / (2×2ˣ - 2²×2ˣ)
… = (4×2ˣ - 8×2ˣ) / (2×2ˣ - 4×2ˣ)
… = (4<em>y</em> - 8<em>y</em>) / (2<em>y</em> - 4<em>y</em>)
… = (-4<em>y</em>) / (-2<em>y</em>)
… = 2
Answer:
the number that occures the most is the answer
Step-by-step explanation:
Answer:
Esma can fit 3 packages in the box because 20+10+10=30 and 5+2+2=9 so if you add up 9 three times you get 27 and that is the closest number you can get before going over.
Step-by-step explanation:
To solve we need to use Pythagoras theorem (
)
There are 2 possible lengths for x: hypotenuse or one of the 2 shorter sides.
Hypotenuse:
10^{2} + 21^2 =
100+441=
23.3≈x
Shorter leg:
= 441-100
x≈18.47
