What is the equation for x in the diagram ?

The product of two mixed numbers x and y is 10. If x= _ 2/3 and y=_ 3/4 ,<br> find x and y?

Akimi4 [234]

Answer:

x = 2 2/3
y = 3 3/4

Step-by-step explanation:

There may be other ways to do this. Here's the approach I took. Let the integer part of x be represented by "a", and the integer part of y be represented by "b". Now, we have ...

(a +2/3)(b +3/4) = 10

Multiplying by 12, this becomes ...

(3a +2)(4b +3) = 120

There are only 16 divisors of 120, so they can be easily enough checked one at a time.

120 = 1·120 = 2·60 = 3·40 = 4·30 = 5·24 = 6·20 = 8·15 = 10·12

Of these divisors, the ones that are of the form 3a+2 are ...

2, 5, 8, 20 . . . . a=0, 1, 2, 6

The ones that are of the form 4b+3 are ...

3, 15 . . . . b = 0, 3

The factor pair that consists of a number on the first list and a number on the second list is ...

120 = 8·15

corresponding to a=2 and b=3. So, the mixed numbers you want are ...

x = 2 2/3

y = 3 3/4

_____

<em>Check</em>

(2 2/3)·(3 3/4) =2·3 +2·3/4 +2/3·3 +2/3·3/4 = 6 +6/4 +2 +2/4 = 8+8/4 = 10

6 0

3 years ago

What is the expanded form for 2.059

Artyom0805 [142]

2+ 0.0+ 0.05+ 0.009okay so you just have to add the numbers. so you add 2+0.0+0.5+0.009. then you will get you answer. i hope this helps!!!!

3 0

3 years ago

Write an equation that is perpendicular to and 3x+y=3 whose y-intercept 5. Anyone please help me, no link just explain how to do

Liula [17]

Answer:

$y = \frac{1}{3}x + 5$

Step-by-step explanation:

By definition, two lines are perpendicular if and only if their slopes are negative reciprocals of each other: $m = - \frac{1}{m_{2} }$ , or equivalently, $m_{1} * m_{2} = -1$ .

Given our linear equation 3x + y = 3 (or y = -3x + 3):

We can find the equation of the line (with a y-intercept of 5) that is perpendicular to y = -3x + 3 by determining the negative reciprocal of its slope, -3, which is $\frac{1}{3}$ .